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attashe74 [19]
3 years ago
7

Can someone help fast ??

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
Use this website wwww.abcs 123.com for the answer blrddd
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ASAP Help me please!!
Anvisha [2.4K]
<h3>Answer:  x = 14</h3>

=============================================

Work Shown:

Refer to the diagram below. I've added a line segment and two variables y and z. This forms two isosceles triangles.

The central angle 56 degrees subtends the same arc as the inscribed angle y. By the inscribed angle theorem, this means y = 56/2 = 28. The inscribed angle is always half of the central angle (when both angles subtend the same arc).

Focus on the smaller isosceles triangle that has angles 56, z and z. Those three angles add to 180

z+z+56 = 180

2z+56 = 180

2z = 180-56

2z = 124

z = 124/2

z = 62

Now focus on the larger isosceles triangle (angles y = 28, x+z and x+z)

We'll use the same trick as before.

(x+z)+(x+z)+(y) = 180

(x+62)+(x+62)+(28) = 180 ... plug in z = 62 and y = 28

2x+152 = 180

2x = 180-152

2x = 28

x = 28/2

x = 14

7 0
2 years ago
Find the domain for the particular solution to the differential equation dy dx equals the quotient of 3 times y and x , with ini
Svetach [21]
For this case we have the following difference equation:
 dy / dx = 3xy&#10;
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 dy / y = 3xdx&#10;
 Integrating both sides we have:
 \int\ ({1/y}) \, dy =  \int\ {3x} \, dx
 ln (y) = (3/2) x ^ 2 + C&#10;
 applying exponential to both sides:
 exp (ln (y)) = exp ((3/2) x ^ 2 + C)&#10;&#10; y = C * exp ((3/2) x ^ 2)
 For y (1) = 1 we have:
 C = 1 / (exp ((3/2) * 1 ^ 2))&#10;&#10;C = 0.2
 Thus, the particular solution is:
 y = 0.2 * exp ((3/2) x ^ 2)&#10;
 Whose domain is all real.
 Answer:
 y = 0.2 * exp ((3/2) x ^ 2)
 Domain: all real numbers
6 0
3 years ago
5)Express in standard form: (i)4809000 (ii)0.00849​
zysi [14]

Answer:

I hope it helps .in case you don't understand any part ,feel free to ask.

6 0
1 year ago
What is the formula for intersecting chords on the interior of a circle?​
Ratling [72]

Answer:

Each chord is cut into two segments at the point of where they intersect. One chord is cut into two line segments A and B. The other into the segments C and D. This theorem states that A×B is always equal to C×D no matter where the chords are.

4 0
2 years ago
Which of the following are valid names for the given triangle? Check all that apply.
vfiekz [6]
When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT
6 0
2 years ago
Read 2 more answers
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