The expected value of the number of points for each turn is 0.25
<h3>What is expected value?</h3>
Expected value describes the long term average level of a random variable based on its probabilty distribution.
Now, Probability that 2 heads come up is
P(2 is H) = 1/4
Probability that 1 heads come up is
P(1 is H) = 2/4
⇒P(1 is H) = 1/2
Probability that no head will come up
P(no H's) = 1/4
Hence, the expected value for winning of 2points, 1point and lose of3 points is given as-
Expected value = 2 * P(2 is H) + 1 * P(1 is H) - 3 * P(no H's)
⇒Expected value = 2 * 1/4 + 1 * 1/2 - 3 * 1/4
= 0.5 + 0.5 - 0.75
⇒Expected value = 0.25
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Short Answers
P(Both) = 0.1792
Givens
The total number of roles = 100
Total number of heads = 56
Number of times rolled a four = 32 [check this for me].
Set up the probabilities.
P(H) = 56/100
P(4) = 32/100
P(H)*P(4) = P(Both)
Substitute and solve
P(Both) = 56/100 * 32/100 = 1792/10000
P(Both) = 112/625 because there are many cancellations. Or you could just express it as 0.1972
Answer:1/2=2/4=4/8
Step-by-step explanation:It's quite simple if you do 1/2 times 2 you would get 2/4 1*2=2 2*2=4 2/4 same with 2/4 time 2 2*2=4 4*2=8 4/8.
