Answer:
3,400 g
Step-by-step explanation:
The computation of the grams of trail he left is shown below:
As we know that
1 kg = 1000g
So for 12 kg it is = 12000 g
And, his family ate 8,600 g mix on the hiking trip
So, the trial mix did he have left is
= 12,000 g - 8,600 g
= 3,400 g
Exponents and logarithms are inverse functions, which means that exponents are the way to "undo" logarithms and logarithms are what you use to "undo" exponents. exponents tell you how many times you have to multiply a value and logarithms ask which exponent you need to use to get a specified value. exponential equations are used in a lot of scientific fields; for example, in biology, they're used to calculate the half-life of organisms. they can also be used to estimate the growth of a population. additionally, the richter scale, which measures the magnitude of earthquakes, uses logarithms.
Answer:
Step-by-step explanation:
First, you need to find the fraction of the passengers who are not senior citizens. Add 1/5 and 2/3 to get 13/15.
This means that 13/15 of the passengers aren't senior citizens and 2/15 of the passengers are senior citizens.
Hope i helped!
Answer:
f(-3) = -20
Step-by-step explanation:
We observe that the given x-values are 3 units apart, and that the x-value we're concerned with is also 3 units from the first of those given. So, a simple way to work this is to consider the sequence for x = 6, 3, 0, -3. The corresponding sequence of f(x) values is ...
34, 10, -8, ?
The first differences of these numbers are ...
10 -34 = -24
-8 -10 = -18
And the second difference is ...
-18 -(-24) = 6
For a quadratic function, second differences are constant. This means the next first-difference will be ...
? -(-8) = -18 +6
? = -12 -8 = -20
The value of the function at x=-3 is -20.
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The attachment shows using a graphing calculator to do a quadratic regression on the given points. The graph can then be used to find the point of interest. There are algebraic ways to do this, too, but they are somewhat more complicated than the 5 addition/subtraction operations we needed to find the solution. (Had the required x-value been different, we might have chosen a different approach.)