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zlopas [31]
3 years ago
5

A line has an x - intercept of 0. What is the y-intercept?

Mathematics
1 answer:
garri49 [273]3 years ago
6 0
A line who's x-intercept is 0, would have a y-intercept that is also 0.

This is because, lines go in straight lines, and don't curve. So if it intercepts at 0 on x, it'll intercept at the origin, making the y-int 0.

I hope this helps!
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A school typically sells 500 yearbooks each year for $50. The economics class does a project and discovers that they can sell 10
padilas [110]

Answer:

a is 100 b is 5

Step-by-step explanation:

a is 100 because if you substitute 100 for a and 1 for x (decrease of 5 dollars) you get 600 yearbooks sold which is a curate according to the economics class prediction

b is 5 because substituting 5 into b and 1 to x gives you 45 dollars per year book. this is accurate because a 5.dollar decrease in price makes the year books 45 dollars instead of 50

7 0
3 years ago
According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
3 years ago
Choose the system of equations which matches the following graph:
Kipish [7]

3x - 2y = 8

- 2y = 8 - 3x

2y = 3x - 8

y = 1.5x - 4

This is the red graph

6x - 4y = 20

- 4y = 20 - 6x

4y = 6x - 20

y = 1.5x - 5

This is the blue one.

So it must be answer d)

3 0
3 years ago
PLZZZ HELP RN ASAP TYSM
murzikaleks [220]
It would probably be 56.55
6 0
3 years ago
Subtract. Write your answer as a fraction in simplest form.<br><br> 5/8 - (-7/8)= ???
Doss [256]
The answer has a mixed reaction is 1 1/2 but as an improper fraction is it 3/2!
8 0
3 years ago
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