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3 years ago

F(x) = log3(x + 4) Find f-1(2)

Mathematics

1 answer:

mezya [45]3 years ago

4 0

Answer:

The vertical asymptote of the log function is normally x=0. In this function, it is moved to the right 1 unit. That is accomplished by replacing the function argument x with (x-1). Only one answer choice matches:

f(x) = log3(x -1) +1

Step-by-step explanation:

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Someone please help me with math linear equations 3x + 2y = 12

vodka [1.7K]

3x + 2y = 12
subtract 3x from both sides
2y = -3x + 12
divide all terms by 2 so that you can have only the y on the left side
y = -3/2x + 6
And that is your answer!

Hope this helped!! :)

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3 years ago

Please help me to solve this

natka813 [3]

5) all you have to do is calculate which would be 2.9166...
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3 years ago

Read 2 more answers

There are 15 animals in a barn. These animals are horses and chickens. There are 44 legs in all. Write a system of equations tha

olganol [36]

Answer:

7 horses and 8 chickens

Step-by-step explanation:

To solve this, first you would need to list out all of the available ratios. Then, find out how many legs are in each option.:

14 horses and 1 chicken = 58 legs

13 horses and 2 chickens = 56 legs

12 horses and 3 chickens = etc.

11 horses and 4 chickens

10 horses and 5 chickens

9 horses and 6 chickens

8 horses and 7 chickens

7 horses and 8 chickens = 44 legs!

6 horses and 9 chickens

5 horses and 10 chickens

4 horses and 11 chickens

3 horses and 12 chickens

2 horses and 13 chickens

1 horses and 14 chickens

5 0

3 years ago

Please help me with this!!

Naddik [55]

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the $x$ values in the table. In other words, we need to replace $x$ with each value in our given function and simplify.

- For x = 0

$f(x)=(x-2)^2-5$

$f(0)=(0-2)^2-5$

$f(0)=(-2)^2-5$

$f(0)=4-5$

$f(x)=-1$

Since $x=0$ and $y=-1$ , our first point is (0, -1)

- For x = 1

$f(x)=(x-2)^2-5$

$f(1)=(1-2)^2-5$

$f(1)=(-1)^2-5$

$f(1)=1-5$

$f(x)=-4$

Our second point is (1, -4)

- For x = 2

$f(x)=(x-2)^2-5$

$f(2)=(2-2)^2-5$

$f(2)=(0)^2-5$

$f(x)=-5$

Our third point is (2, -5)

- For x = 3

$f(x)=(x-2)^2-5$

$f(3)=(3-2)^2-5$

$f(3)=(1)^2-5$

$f(3)=1-5$

$f(x)=-4$

Our fourth point is (3, -4)

- For x = 4

$f(x)=(x-2)^2-5$

$f(4)=(4-2)^2-5$

$f(4)=(2)^2-5$

$f(4)=4-5$

$f(x)=-1$

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

3 0

3 years ago

Angles a and b are supplementary how would you fix value of x

kotykmax [81]

Answer: 180 = 30 + (x + 60)

Step-by-step explanation: Supplementary means that the angles add together to 180 degrees. This equations shows that angle A (30 degrees) plus angle B (x + 60) equal 180. If you solve the equation you will find that angle B is equal to 150 degrees, and that x = 90.

5 0

3 years ago