<span>The dot product here is 10(9) + 6(5)=120
so the vectors are not orthogonal
</span><span>u.v = |u| x |v| cos (theta) ; theta is the angle between them
we know from above that u.v = 120
|u| = sqrt[10^2+6^2]=11.66
|v| = sqrt[9^2+5^2]=10.29
so we know:
theta =cos^-1 120/(11.66x10.29)
so theta = 25 degrees</span><span>
</span>
Answer:
(3,-2)
Step-by-step explanation:
Given equations of line
3x-2y=13
2y+x+1=0
=> x = -1 -2y
Point of intersection will coordinates where both equation have same value of (x,y)
top get that we have to solve the both equations by using method of substitution of simultaneous equation.
using this value of x in 3x-2y=13, we have
3(-1-2y) -2y = 13
=> -3 -6y-2y = 13
=> -8y = 13+3 = 16
=> y = 16/-8 = -2
x = -1 - 2y = -1 -2(-2) = -1+4= 3
Thus, point of intersection of line is (3,-2)
Answer: y=x+5
Step-by-step explanation:
So the dots are going at a slope of 1 up and 1 right each time, so your slope would be 1, or simply x if you times it. To line it up with the slope, you have to move up 5 on your y-axis, known as your b. Then from there, you go up 1 over 1 which will line up with all the dots.
Answer:
work is pictured and shown
The co ordinates could become positive or negative such as point a to b is (1,-2) but point b to a is (-1,2)