3 years ago

333/98+565-5(12+65^43 x 3)?

Mathematics

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

4 is the wrong answer

Step-by-step explanation:

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Square efgh has been reflected across the x axis and then reflected across the y axis which of the following transformations wou

tigry1 [53]

An 180-degreee rotation would return the square to its original position.

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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

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What is the slope of a line perpendicular to the line whose equation is 4x-2y=-16.

Arte-miy333 [17]

Answer:

-1/2

Step-by-step explanation:

the slope of the first line is 2

to get the line perpendicular, you swap the numerator and denominator, then if positive make negative and the other way around

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KonstantinChe [14]

The answer is 3/4. You divide both numbers (54 and 72) by 18 and you get 3/4. Hope it helps!

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I NEED HELP FAST PLEASE :)

user100 [1]

Answer:945

Step-by-step explanation:

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