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3 years ago

1. Sølve the following equation: (3x – 5)1/4 = 2

Mathematics

2 answers:

AfilCa [17]3 years ago

5 0

Answer:

Step-by-step explanation:

$(3x-5)*\frac{1}{4}=2\\\\\frac{3x-5}{4}=2\\\\3x-5=2*4\\\\3x-5=8\\\\3x=8+5\\\\3x=13\\\\x=\frac{13}{3}$

garri49 [273]3 years ago

4 0

Answer:

13.3

4.33

4 1/3

Step-by-step explanation:

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4 years ago

Solve the missing side. Find the missing side. Round to the nearest tenth. Please show the work. Part 2. #5-8

enyata [817]

Answer:

5. 6.1 units

6. 29.4 units

7. 12.8 units

8. 29.1 units

Step-by-step explanation:

5. We have the opposite and adjacent sides here for angle 21 degrees. So we need to use tangent, which is opposite / adjacent:

$tan(21)=x/16$

$x=16*tan(21)$ ≈ 6.1 units

6. We have the opposite and hypotenuse sides here for angle 33 degrees. So we need to use sine, which is opposite / hypotenuse:

$sin(33)=16/x$

$x=16/sin(33)$ ≈ 29.4 units

7. We have the opposite and adjacent sides here for angle 37 degrees. So we need to use tangent, which is opposite / adjacent:

$tan(37)=x/17$

$x=17*tan(37)$ ≈ 12.8 units

8. We have the opposite and hypotenuse sides here for angle 31 degrees. So we need to use sine, which is opposite / hypotenuse:

$sin(31)=15/x$

$x=15/sin(31)$ ≈ 29.1 units

Hope this helps!

4 0

3 years ago

Read 2 more answers

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

Please help me!!!!!!!

Lera25 [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Trevor had 4 small boxes of raisins to share equally among himself and 2 friends.

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each person would receive 4/3 of a box of raisins

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