All categories

3 years ago

How do I find the area of a parallelogram and trapezoid

1 answer:

5 0

Parallelogram Area Formula:
Area= base * height

A= bh

Trapezoid Area Formula:
Area= 1/2height * (base1 + base2)

A= 1/2h(b1 + b2)
OR
A= (b1 + b2)/2 * h

This formula can be written and done a couple different ways, and the result will be the same. Note that base1 may be the top edge of a trapezoid and base2 may be the bottom edge. If you have some specific examples, feel free to post them.

Hope this helps a bit! :)

You might be interested in

Which of the following hace a value equal to |37|? Select all that apply

daser333 [38]

B, D, and E
The absolute value of -37 is 37.
The absolute value of 37 is also 37.
When you distribute the negative in the parenthesis the -37 becomes positive.

3 0

3 years ago

Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through

stiks02 [169]

Answer:

$x + 2y= 2$

Step-by-step explanation:

Given

Points:

$F = (4,9)$

$G = (1,3)$

Required

Determine the equation of line that is perpendicular to the given points and that pass through $(2,0)$

First, we need to determine the slope, m of FG

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$F = (4,9)$ --- $(x_1,y_1)$

$G = (1,3)$ --- $(x_2,y_2)$

$m = \frac{3 - 9}{1 - 4}$

$m = \frac{- 6}{- 3}$

$m =2$

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

$m_2 = -\frac{1}{m}$

$m_2 = -\frac{1}{2}$

The equation of the line is then calculated as:

$y - y_1 = m_2(x - x_1)$

Where

$m_2 = -\frac{1}{2}$

$(x_1,y_1) = (2,0)$

$y - 0 = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}x + 1$

Multiply through by 2

$2y = -x + 2$

Add x to both sides

$x + 2y= -x +x+ 2$

$x + 2y= 2$

Hence, the line of the equation is $x + 2y= 2$

8 0

3 years ago

Read 2 more answers

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

3 years ago

A sporting goods store randomly sampled three groups of 100 customers on what their favorite spectator sport is. The data shows

-BARSIC- [3]

Answer:

it is 551!

Step-by-step explanation:

I just took the test! Please give me the brainliest!

3 0

3 years ago

Read 2 more answers

It would really help if someone could tell me the answers for those questions

vazorg [7]

1) 2.4

2) 6.4

3) 7.7

4) 9.9

5) 2.8

Hope it helps <3

Just basic simplification, make 1 of the variable alone on one side

5 0

3 years ago