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RoseWind [281]
3 years ago
15

Please answer this question 4(x+y)+2(x+z)​

Mathematics
2 answers:
Colt1911 [192]3 years ago
7 0

Answer:

6x +4y+2z

Step-by-step explanation:

4(x+y)+2(x+z)​

Distribute

4x+4y +2x+2z

Combine like terms

6x +4y+2z

frez [133]3 years ago
4 0

expand the brackets

4x+4y + 2x +2z

6x + 4y + 2z

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The square root of a prime number (11) is irrational
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Solve the equation y=2x^2-x-6 using the quadratic formula show the steps to solving
saul85 [17]

Answer:

x1 = 2 \\ x2 =  -  \frac{3}{2}

Step-by-step explanation:

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}  \\ x =  \frac{1 +  -  \sqrt{ {( - 1)}^{2} - 4(2)( - 6) } }{2(2)}  \\ x =  \frac{1 +  -  \sqrt{1  + 48} }{4}  \\ x =  \frac{1 +  -  \sqrt{49} }{4}  \\ x =  \frac{1 +  - 7}{4}  \\  \\ x1 =  \frac{1  + 7}{4}  =  \frac{8}{4}  = 2 \\ x2 =  \frac{1 - 7}{4}  =   - \frac{6 }{4}  =  -  \frac{3}{2}

7 0
4 years ago
( 3 x 2 ) ^ 4 x 3 ^ -3 / 2 ^ 3 x 3 =<br><br> Simplify the exponential expression
Korvikt [17]

Answer:

2

Step-by-step explanation:

\frac{(3*2)^4*3^{-3}}{2^3*3}

we start simplifying by removing the parenthesis

Multiply the exponents inside the the parenthesis

3^4  * 2^4

\frac{3^4*2^4*3^{-3}}{2^3*3}

Now we apply exponential property

a^m * a^n = a^ (m+n)

3^4 * 3^-3 = 3^ (4-3) = 3^1

3 or 3^1  are same

\frac{3^1*2^4}{2^3*3^1}

3^1 at the top and bottom so we cancel it out

\frac{2^4}{2^3}

we apply log property . a^m / a^n = a^m-n

Now subtract the exponents

2^(4-3) = 2^1 = 2



4 0
4 years ago
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loris [4]
Remember that both the denominator and the square root function cannot have values less than 0.  So to figure what values can go into each we need to do a little math.  Set both the denominator and the under the radical equal to 0
x + 2 = 0            x - 3 = 0
x = -2                 x = 3

Since they must be those numbers or bigger 3 is the larger of the 2 the final answer is
x >= 3  Type in greater than into the box
7 0
4 years ago
Please help this is 5th Grade Math also show work 15 Points awarded
Dimas [21]

Answer:

The only one that would be reasonable is the first one...and maybe the third one too

Step-by-step explanation:


8 0
3 years ago
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