The square root of a prime number (11) is irrational
Answer:

Step-by-step explanation:

Answer:
2
Step-by-step explanation:

we start simplifying by removing the parenthesis
Multiply the exponents inside the the parenthesis
3^4 * 2^4

Now we apply exponential property
a^m * a^n = a^ (m+n)
3^4 * 3^-3 = 3^ (4-3) = 3^1
3 or 3^1 are same

3^1 at the top and bottom so we cancel it out
\frac{2^4}{2^3}
we apply log property . a^m / a^n = a^m-n
Now subtract the exponents
2^(4-3) = 2^1 = 2
Remember that both the denominator and the square root function cannot have values less than 0. So to figure what values can go into each we need to do a little math. Set both the denominator and the under the radical equal to 0
x + 2 = 0 x - 3 = 0
x = -2 x = 3
Since they must be those numbers or bigger 3 is the larger of the 2 the final answer is
x >= 3 Type in greater than into the box
Answer:
The only one that would be reasonable is the first one...and maybe the third one too
Step-by-step explanation: