29) First of all when I write “^2” I mean to the power of 2. Label the bottom line Z or whatever u fancy. Then make 3 equations to solve simultaneously using a^2+b^2=c^2
(1) 14^2+y^2=Z^2
(2) 6^2+y^2=x^2 and (3) x^2+z^2=20^2
The next step is to solve them simultaneously e.g you can rearrange (2) to give you y^2=x^2-6^2 and then input that into (1) to get 14^2+x^2-6^2=Z^2 and again you rearrange (3) to get z^2=20^2-x^2 and input that in and solve for x. Then you will have to repeat that solving for y and only y as the question doesn’t originally ask for z but only for the values of x and y I assume. Using this idea, from glancing at the other questions you should be able to apply this concept to those other questions, if not then make another post outlining any specific questions
Answer:
h = 3v/b
Step-by-step explanation:
Here, we want to select the equation that solves for h
What this simply means is that we should make h the subject of the formula
Thus, we have 3 * v = bh
3v = bh
h = 3v/b
Answer:
Step-by-step explanation:
He would be 87 years old right now
Answer:
44 square cm
Step-by-step explanation:
Area= LxW
=33x10
=330feet
Perimeter =L+W+L+W
=33+10+33+10
=86feet
Hope this helps :)
