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bulgar [2K]
3 years ago
12

What is the distance between points S and T?

Mathematics
2 answers:
Margarita [4]3 years ago
8 0

Answer:  16 units

Step-by-step explanation:

The distance between any two points x_1 and x_2 on a number line is given by :-

d=|x_2-x_1|

From the given picture, there is a number line where point S is at -2 and point T is at 14.

Then, the distance between points S and T will be :_

d=|14-(-2)|\\\\\Rightarrow\ d=|14+2|=|16|=16\text{ units}

Hence, the distance between points S and T = 16 units

Alex_Xolod [135]3 years ago
7 0
The distance between points S and T is 16.
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Answer correctly please
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
(10v^4 + 30v^3 + 2v^2) / 10v
Zina [86]

Given expression is

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4 years ago
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5 0
3 years ago
Read 2 more answers
On a coordinate plane, parallelogram R S T U has points (negative 4, 4), (2, 6), (6, 2), and (0, 0). What is the area of paralle
Ad libitum [116K]

Answer:

The area of the parallelogram is;

32 square units

Step-by-step explanation:

The given parameters are;

The coordinates of the parallelogram RSTU = R(-4, 4), S(2, 6), T(6, 2), and U(0, 0)

We note that the area of a parallelogram = Base length × Height

From the drawing of the parallelogram RSTU, we have;

The base length = The length of \overline {TU} = The length of \overline {SR} = √((2 - (-4))² + (6 - 4)²) = 2·√10

The height of a parallelogram is perpendicular to its base length = The line \overline {VT}

∴ Where, the slope of the base length = m, the slope of the height = -1/m

The slope, 'm' of \overline {SR} = (6 - 4)/(2 - (-4)) = 1/3

Therefore, the slope of the height = -1/(1/3) = -3

We note that a point on the height is the point 'T', therefore, the equation of the line in point and slope form is therefore;

y - 0 = -3·(x - 0)

∴ y = -3·x

Therefore, the coordinates of the point 'V' is given by the simultaneous solution of the equations of \overline {SR} and \overline {VT}

The equation of the line \overline {SR} in point and slope form from the point 'R' and the slope 'm = 1/3' is given as follows;

y - 4 = (1/3) × (x - (-4)) = (1/3) × (x + 4)

y = x/3 + 4/3 + 4 = x/3 + 16/3

y = x/3 + 16/3

We then have the coordinate at the point 'V' (x, y) is given as follows;

-3·x = x/3 + 16/3

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-10·x = 16

x = -16/10 = -1.6

x = -1.6

∴ y = -3·x = -3 × -1.6 = -4.8

y = 4.8

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The length of the line \overline {VT} = The height of the parallelogram = √((-1.6 - 0)² + (4.8 - 0)²) = 8/5·√10

The height of the parallelogram = 8/5·√10

The area of the parallelogram, A = Base length × Height

∴ A = 2·√(10) × 8/5·√(10) = (16/5) × 10 = 32

The area of the parallelogram, A =  32 square units.

6 0
3 years ago
Read 2 more answers
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