All categories

2 years ago

Use the substitution method to determine the solution to the system of equations below. y-2x+2=1 6x-3y=3

Mathematics

1 answer:

vesna_86 [32]2 years ago

4 0

Answer:

y-2x=-1

y=-1+2x

y=-(2x-1)

y=-2x+1---->

6x-3y=3 (or 2x-y=1)

2x-(-2x+1)=1

2x+2x-1=1

4x=2

x=1/2

-------------

subtitate 1/2

y-2(1/2)=-1

y-1=-1

y=0

hope it helps you

You might be interested in

Is this a function or not?

Hoochie [10]

Answer:

ummm it think so

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

a recent survey determained that 7 out of 9 students eat school lunch at least once a week. if 54 students were surveyed how man

Setler [38]

Answer:

12 students

Step-by-step explanation:

Given

$Students = 54$

Required

Determine the number of students that eat lunch once a week

In Sets;

If out of 9, at least 7 eats one a week then

9 - 7 eats lunch once a week

$9 - 7 = 2$

<em>In other words;</em>

2 out of 9 students eat lunch once a week

Number of students in this category is then calculated as thus;

$Number = \frac{2}{9} * 54$

$Number = \frac{2 * 54}{9}$

$Number = \frac{108}{9}$

$Number = 12$

3 0

3 years ago

Write 5/10 in 3 equivalent forms

son4ous [18]

5/10 in 3 equivalent forms is: 1/2 2/4 4/8

7 0

3 years ago

Which equation has no solution?

kherson [118]

A because absolute values are always more than or equal to 0

7 0

3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

4 years ago

Use the substitution method to determine the solution to the system of equations below. y-2x+2=1 6x-3y=3​

Use the substitution method to determine the solution to the system of equations below. y-2x+2=1 6x-3y=3