Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
Answer:
Step-by-step explanation:
2ab - 4b
Taking 2b as common
2b( a - 2)
Answer:
Where is the a. b. c. or d?
Answer:
no!!
Step-by-step explanation:
it's b!! simply solve for y by subtracting both sides by 3x and then dividing both sides by 2
Answer:
3.75
Step-by-step explanation:
1.5 equals 30 ft so x2 equals 60 then 15 is half of 20 so half of 1.5 in is .75 so 3 plus .75
