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shtirl [24]
3 years ago
13

A man deposits $ 14,850 into a bank, which pays 4% interest that is compounded

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0

Given:

Principal = $14850

Rate of interest = 4% compounded semiannually.

Time = 3 years

To find:

The amount after 3 years.

Solution:

Formula for amount is:

A=P\left(1+\dfrac{r}{n}\right)^{nt}

Where, P is principal, r is the rate of interest in decimal, n is the number of times interest compounded and t is the number of years.

The interest is compounded semiannually, so n=2.

Putting P=14850, r=4, n=2, t=3 in the above formula, we get

A=14850\left(1+\dfrac{0.04}{2}\right)^{2(3)}

A=14850\left(1+0.02\right)^{6}

A=14850\left(1.02\right)^{6}

On further simplification, we get

A=14850(1.12616242)

A=16723.511937

A\approx 16723.51

Therefore, the amount in the account after three years is $16723.51.

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State the order and type of each transformation of the graph of the function
algol [13]

Using translation concepts, compared to the graph of the base function g(x) = x², the function f(x) was:

  • Vertically stretched by a factor of 4.
  • Shifted left by 9 units.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the base function g(x) = x² was:

  • Multiplied by 4, that is, vertically stretched by a factor of 4.
  • Shifted left 9 units, as x -> x + 9.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

6 0
2 years ago
Need help with this I'm on a time limit
OverLord2011 [107]
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-Brainly support team (Klara academic DEPT.)Spam words mean team is having trouble determining the question CONTACT For support. Thanks for using brainly.
7 0
3 years ago
I don’t really get this one.<br> Thx and have a great day!!
gayaneshka [121]

Answer:

The correct option is C). (9,4)

The coordinates of a point N is (9,4)

Step-by-step explanation:

Theory: If point P(x,y) lies on line segment AB and AP: PB=m:n, then we say P divides line AB internally in ratio of m:n and Point is given by

P=(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})

Given that point, M is lying somewhere between point L and point N.

The coordinates of a point L is (-6,14)

The coordinates of a point M is (-3,12)

Also, LM: MN = 1:4

We can write as,

Let,

Point L(-6,14)=(X1, Y1)

Point M(-3,12)=(x,y)

Point N is (X2, Y2)

m=1 and n=4

M(-3,12)=(\frac{mX2+nX1}{m+n} , \frac{mY2+nY1}{m+n})

M(-3,12)=(\frac{1(X2)+4(-6)}{1+4} , \frac{(Y2)+4(14)}{1+4})

M(-3,12)=(\frac{(X2)-24}{5} , \frac{1(Y2)+56}{5})

(-3)=\frac{(X2)-24}{5}

(-15)=X2-24

X2=9

(12)=\frac{(Y2)+56}{5}

(60)=Y2+56

Y2=4

Thus,

The coordinates of a point N is (9,4)

Result: The correct option is C). (9,4)

3 0
3 years ago
2 pts
katrin2010 [14]

Answer:

It is a binomial and the degree is 9

4 0
3 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
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