Answer:
377 choices
Step-by-step explanation:
The following values were given in the question:
The restaurant offered
6 choices of appetizer
8 choices of main meal
5 choices of dessert.
We are also told in the question that the customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
B = Main meal = 8
C = Dessert = 5
a) The 3 choices together
ABC=6 × 8 × 5=240 choices
b) AB= Appetizer and Main meal
= 6 × 8 = 48 choices
c) AC= Appetizer and Dessert
= 6 × 5 = 30 choices
d) BC = Main meal × Dessert
= 8 × 5 = 40 choices
e) A,B,C = the customer having each of the choices only
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19 choices
The number of possible meals is calculated as:
240 choices + 48 choices + 30 choices + 40 choices + 19 choices
= 377 choices
