What I would say is that an x-ray has an insignificant amount of radiation compared to some other things which were exposed on a daily basis and therefore the patient doesn't have to worry about it.
Explanation:
It can be important<span> to comfort the patient </span>to elucidate<span> him/her what X-ray is. </span>however, you're reaching to do it<span> and why. </span>make a case for<span> the patient what the results </span>are reaching to<span> show. </span>offer<span> time </span>to urge ready<span> and prepare. Guide the person slowly </span>within the preparations<span> </span>method<span>, step by step for him/ her to </span>relax.
<span>It is </span>the same<span> that the word "radiation" causes </span>worry<span> not </span>solely<span> in patients </span>however additionally<span> in their families and friends. </span>thus a transparent<span> communication between the </span>skilled and therefore the<span> patient </span>is prime<span> to proceed with the exams </span>sedately<span> and let the patient </span>learn properly<span>.</span>
Answer:
The correct answer is physics.
Explanation:
Health education/promotion includes the knowledge, principles, and concept of may disciplines like biology, sociology, medical science, psychology, etc. So it comes from a variety of discipline but physics is not the major discipline which supports health education and discipline because physics deals with the structure of matter and how the particles and universal constituents interact with each other.
Physics focuses on finding the rules of the universe so it is less related to health education and promotion. Therefore the correct answer is physics.
In this given problem, to solve for the acceleration we have to
assume that the acceleration is constant. This assumption helps us understand
that the velocity of Dave follows a linear increase and hence we can use the
formula below for calculating the acceleration:
a= (Vf – Vi) / t
where
Vf = final velocity = 7.0 m / s
Vi = intial velocity = 3.0 m / s
t = time elapsed = 10 s – 5 s = 5 s
Substituting the known values into the equation:
a = (7.0 m / s – 3.0 m / s) / 5 s
a = 0.8 m / s^2
Answer:
<span>D. 0.8 m/s2</span>