Simplified the expression.
2M^2m^6 / n
-TanqR
Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:28 bags with 17 cents left over
Step-by-step explanation: First, subtract the amount of 37.85 from what he started out with, 52.02. You should get 14.17.
Then, if we have 14 whole dollars and the bags each cost 50 cents, then we can just multiply 14 by 2, since each dollar equals 50 cents times 2.
EX: $1=50 cents x2. So 14 dollars x2 would be like saying the first amount 50 cents doubled. You should get 28 bags, with 17 cents left over :). Let me know if this makes sense! I really hope this helps you.
Answer: No
Step-by-step explanation:
I believe there would only be one describing both if they were parallel lines, but they are going two different directions in this graph. Correct me if I am wrong!
