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3 years ago

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Mathematics

2 answers:

Alla [95]3 years ago

5 0

Define variable- 4.5x
Equation - 15+ 4.5x =42
Solution- x=6

15+ 4.5x =42
4.5x = 27
X=6

Anna35 [415]3 years ago

3 0

The answer is x=6 I hope this helped

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George buys a computer. He pays a deposit of £200 and six monthly instalments of £55. How much does George pay for his computer

Citrus2011 [14]

Answer:

530

Step-by-step explanation:

200+6(55)

6x55=330

200+330=530

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3 years ago

What is the second term of (p+q)^5 1. 25p^4 2. 5p^4q 3. 25p^4q 4. 125p^4q

yaroslaw [1]

I hope this helps you

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3 years ago

Read 2 more answers

Someone please respond I’ve been reposting this question several of times already

seraphim [82]

Answer:

-4

Step-by-step explanation:

If a = -4 then you can eliminate hte -4x and 4x by adding them, you get 0x, so you eliminate the x variable

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3 years ago

What’s the slope for this graphed? A.5 B.1/3 C.2 D.3

larisa [96]

No it’s D because it is rise over run and you rise 3 and run 1. 3/1 is simplified to 3.

6 0

3 years ago

The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t

Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.054\frac{54}{\sqrt{430}} = 5.35$

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0

2 years ago