Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
5 wholes = 5
2 fifths = 2/5
5 - 2/5 = 4 3/5 (4 and 3 fifths)
Answer = 4 3/5
Check work:
4 3/5 + 2/5 = 5 (wholes)
Answer:
Minimum height is 7.25ft and maximum height is 7.75ft
Step-by-step explanation:
You measured to the nearest half foot, so the greatest possible error is 0.25 foot.
Minimum height= measured value-possible error= 7.5-0.25= 7.25ft
Maximum height= measured value+possible error= 7.5+0.25= 7.75ft
Answer:
it is five units
Step-by-step explanation:
