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3 years ago

Which function represents a reflection of f(x) = 2(0.35)x over the y-axis?

2 answers:

7 0

Hello there,
The answer it's <span> h(x)=2(.35)-x aka c for e2020

I hope this helped, and if you have any more question please feel free to ask me.
Have a nice day!
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natta225 [31]3 years ago

7 0

Answer:

$g(x) = 2(0.35)^{-x}$

Step-by-step explanation:

Given is an exponential function with base as 0.35

The function is

$f(x) = 2(0.35)^x$

When this should be reflected over y axis, the y axis will serve as a mirror for the given curve and new curve

y axis has equation as x=0

Hence reflection would be changing sign of x

So answer is

$g(x) = 2(0.35)^{-x}$

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Write the decimal as a percent.<br><br> 0.097

earnstyle [38]

Answer:

9.7%

Step-by-step explanation:

6 0

3 years ago

Write the equation for a line perpendicular to y=-3x+18 that goes through the point (-12,6)

Hatshy [7]

Answer:

$y=\frac{1}{3} x -14$

Step-by-step explanation:

The equation of the line you will find should be in the form y =mx+c , where m is the gradient and c is the y intercept.

The gradient of a line that is perpendicular to a line [of a known gradient] is the negative reciprocal of the gradient of the first. i.e. if a is the known gradient and the perpendicular gradient is b, ab = -1. Therefore the -3b=-1 and b= 1/3

you can now write y = mx +c as y = 1/3x +c

As you have been given a coordinate, you can input these values into y= 1/3x + c

-12 = 1/3(6) +c

-12 - 2 = c

c = -14

hence the equation of the line is y= 1/3x -14

5 0

3 years ago

A jar contains 3 red, 2 white, and 1 green marble. Aside from color, the marbles are indistinguishable. Two marbles are drawn at

IRISSAK [1]

Answer:

0.6

Step-by-step explanation:

A permutation is an arrangement of outcomes whereas a combination is a grouping of outcomes.

Order matters in case of permutations but does not matter in combinations.

Given:

Number of red marbles = 3

Number of white marbles = 2

Number of green marbles = 1

To find: probability of picking 4 marbles and getting one of each color

Solution:

Total number of outcomes = $6_C__4$ = $\frac{6!}{4!\,2!}=\frac{6\times 5\times 4!}{4!\times 2}=15$

Number of favourable outcomes = 2 red, 1 white and 1 green marble + 1 red, 2 white and 1 green marble = $3_C_2\,2_C_1\,1_C_1+3_C_1\,2_C_2\,1_C_1$ = $\frac{3!}{2!\,1!}\times \frac{2!}{1!\,1!}\times 1+\frac{3!}{2!\,1!}\times 1\times 1=6+3=9$

So, probability of picking 4 marbles and getting one of each color = Number of favourable outcomes/Total number of outcomes = $\frac{9}{15}=\frac{3}{5}=0.6$