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Simora [160]
2 years ago
5

Which function represents a reflection of f(x) = 2(0.35)x over the y-axis?

Mathematics
2 answers:
Artist 52 [7]2 years ago
7 0
Hello there,
The answer it's <span> h(x)=2(.35)-x aka c for e2020

I hope this helped, and if you have any more question please feel free to ask me.
Have a nice day!
</span>
natta225 [31]2 years ago
7 0

Answer:

g(x) = 2(0.35)^{-x}

Step-by-step explanation:

Given is an exponential function with base as 0.35

The function is

f(x) = 2(0.35)^x

When this should be reflected over y axis, the y axis will serve as a mirror for the given curve and new curve

y axis has equation as x=0

Hence reflection would be changing sign of x

So answer is

g(x) = 2(0.35)^{-x}

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mestny [16]
Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

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3 years ago
Ok so I need help thank you
Liula [17]

Answer:

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Step-by-step explanation:

I'm pretty sure, I'm sorry if its wrong

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2 years ago
Write an equation of the line perpendicular to the line 8x+15y=12 and containing the point (11,17) write the answer in standard
jek_recluse [69]

The slope of a line perpendicular to another line has a slope which is the negative reciprocal of that line or:

m1 = -1/m2

First, we convert the given equation into slope-intercept form of a line: y = mx + b

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15y = -8x + 12

y = (-8/15) x + 0.8

m1 = -8 / 15

 

Therefore the slope of the perpendicular line is:

m2 = 15 / 8

 

Since the perpendicular line crosses the point (11, 17), therefore using the slope formula:

m = (y2 – y1) / (x2 – x1)

15 / 8 = (y2 – 17) / (x2 – 11)

1.875 (x2 – 11) = y2 – 17

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y2 = 1.875 x2 – 3.625

y = (15/8) x – 3.625

multiplying both sides by 8:

8y = 15x – 29

rewriting in standard form:

<span>15x – 8y = 29                (ANSWER)</span>

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Wendy purchased 9 pizzas for x dollars. She spent a total of $85.50. Find the value of x
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