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Amanda [17]
4 years ago
15

What are the missing statements in steps 6 and 10 of the proof? Statement 6: Statement 10: Statement 6: || Statement 10: || Stat

ement 6: Statement 10: AEB BEC Statement 6: Statement 10: Statement 6: ABC BCD Statement 10: BAD ADC NextReset
Mathematics
2 answers:
Anuta_ua [19.1K]4 years ago
7 0

Answer:

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

Step-by-step explanation:

leva [86]4 years ago
5 0
I have the same question I need help with
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Solve for x if log 9 base x + log 3 base x^2 = 2.5​
Y_Kistochka [10]

Not sure if the equation is

\log_9x+\log_3(x^2)=\dfrac52

or

\log_x9+\log_{x^2}3=\dfrac52

  • If it's the first one:

9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}

9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}

9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}

9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}

9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}

9^{\log_9x+\log_3(x^2)}=x\cdot x^4

9^{\log_9x+\log_3(x^2)}=x^5

On the other side of the equation, we'd get

9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5

Then

x^5=3^5\implies\boxed{x=3}

  • If it's the second one instead, you can use the same strategy as above:

x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}

x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}

(Note that this step assume x>0)

x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}

x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}

x^{\log_x9+\log_{x^2}3}=9\sqrt3

Then we get

9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}

6 0
3 years ago
What is the approximate area of the circle shown below
meriva

Answer:

D. 154

Step-by-step explanation:

Formula

pi×r^2

r=diameter / 2

14/2=r=7

pi×7^2=154

5 0
3 years ago
A triangle cannot have one obutse angle and one right angle. True or flase?
kykrilka [37]

Answer:

No

Step-by-step explanation:

Since an equilateral triangle has equal sides and angles, each angle measures 60°, which is acute. Therefore, an equilateral angle can never be obtuse-angled. A triangle cannot be right-angled and obtuse angled at the same time. Since a right-angled triangle has one right angle, the other two angles are acute.

4 0
2 years ago
Read 2 more answers
How do you find a nonzero rational number closed under division
vredina [299]

For rational numbers to be closed under division, then any rational number divided by another rational number would have to be a rational number. This works for every rational number except when the second number is 0. Since division by 0 is undefined, dividing any rational number by the rational number zero will not give you a rational number. In order to make the rational numbers closed under division, you can choose any rational number you want except 0.

In other words, the set of rational numbers is not closed under division. The problem occurs only with division by zero. The set of rational numbers from which zero is removed is closed under division.

Every nonzero rational number is closed under division.

6 0
3 years ago
Mitch made a dot plot of the number of hours that students in his grade spent this week watching television. Use the data to cho
tekilochka [14]

Answer:

the first one is false

second one is True

Third one is false

fourth one is false

Step-by-step explanation:

I just looked at the chart please mark me brainlest answer

3 0
3 years ago
Read 2 more answers
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