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Amanda [17]
3 years ago
15

What are the missing statements in steps 6 and 10 of the proof? Statement 6: Statement 10: Statement 6: || Statement 10: || Stat

ement 6: Statement 10: AEB BEC Statement 6: Statement 10: Statement 6: ABC BCD Statement 10: BAD ADC NextReset
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

Step-by-step explanation:

leva [86]3 years ago
5 0
I have the same question I need help with
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What is the result of isolating y2 in the equation below?<br><br> (x - 2)^2 + y2 = 64
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APEX ! Non-linear systems of equation. 

4 0
3 years ago
TIVITY MODULE
bezimeni [28]

Answer: Length: 4, width: 6

Step-by-step explanation:

Let the length be x and width be y

Then x=2y-8 and xy=24

Substitute to get 2y-8 * y = 24, so 2y^2-8y=24 or y^2-4y=12, then solve to get y=6 or y=-2. Since width is positive y=6.

Substitute y=6 into xy=24 to get x=4.

Length: 4, width: 6

Hope that helped,

-sirswagger21

6 0
3 years ago
How do I solve for x
Alchen [17]
Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
a^2+b^2=c^2

Input the information from the diagram into the formula: 
(x)^2+(x+7)^2=(13)^2

Expand each term:
(x)^2+(x+7)^2=(13)^2

x^2+((x+7)(x+7))=169

x^2+(x(x+7)+7(x+7))=169

x^2+x^2+7x+7x+49=169

Combine like terms:
2x^2+14x+49=169

Add -169 to both sides:
(2x^2+14x+49)+(-169)=(169)+(-169)

2x^2+14x-120=0

Factor out the Common Term (2):
2(x^2+7x-60)=0

Factor the Complex Trinomial:
2(x^2-5x+12x-60)=0

2(x(x-5)+12(x-5))=0

2(x-5)(x+12)=0

Set Factors to equal 0:
x-5=0

x=5

or

x+12=0

x=-12

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is: 
\boxed{x=5}

I hope this helped!
-Benjamin

6 0
2 years ago
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