Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.
Answer:
Step-by-step explanation:
If we choose chairs having odd number in the row
no of chairs from which selection is made = 10
no of chairs to be selected = 5
no of ways = 10C₅
similarly if we choose hairs having even numbers only ,
similar to above , no of ways
= 10C₅
Total no of ways
= 2 x 10C₅
= 2 x 10 x 9 x 8 x 7 x 6 / 5 x 4x3 x 2 x 1
= 504 .
Hi!
This is definitely a trapezoid, as it has two equal sides and two inequal sides. It's not a parallelogram, because two sides eventually intersect. It is a quadrilateral, because it has four sides.
None of the others apply here.
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20
There are 10 feet of posts on each side. That means there are 40 feet of fencing in total. If you divide that by two (to represent posts being 2 feet apart) then you get 20. There are 20 posts needed.
Answer:
Ok
Step-by-step explanation:
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