The ether, CH3OCH2CH3, can be prepared by two different nucleophilic substitution reactions, one using CH3O– as nucleophile and
the other using CH3CH2O– as nucleophile. Draw both routes.
1 answer:
Answer:
The routes are in the attached figure bellow.
Explanation:
In order to have a nucleophilic substituition, we need a substract with a positive or partially positive carbon. Therefore, the two possible substracts chosen were alkyl halides. The chlorine is more electronegative than the carbon, therefore the electronic density will be deslocated towards the Cl atom an the C atom will be left partially positive.
The nucleophiles given have strong negative charges and will attack the partially positive carbon. The chlorine will then leave the molecule (leaving group) and a new bond between the carbon and the oxigen will be formed.
Both routes will involve a Sn2 mechanism, which means that the reactions will occur in one step.
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