Explanation:
Given :
Amount of solute - sucrose (C12H22O11) = 41 g
Amount of solvent -soda = 355-mL
Molarity of the solution with respect to sucrose= ?
Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.
Formula to find the molarity of solution :
Molarity =
Amount of solvent is given in mL, let’s convert to L :
1 L = 1000 mL
Therefore, 355 mL in L will be :
= 0.355 L
We have the amount of solute in g, let’s calculate the number of moles first :
Number of moles (n) =
Molar mass of C12H22O11 = 342.29 g/mol.
Therefore, n =
= 0.119 moles.
Answer:
Explanation:
The physical methods of separating mixtures are used in sorting a mixture of substances.
It requires no chemical changes occurring between their components and parts in any significant way.
Examples are:
- Decantation
- Filtration
- Sublimation
- Magnetism
- Centrifugation
The methods simply relies on the physical properties of matter.
Answer:
The top right box
Explanation:
during a lunar eclipse, the earth is in between the sun and moon
Taking into account the stoichiometry of the reaction, 34.12 grams of LiOH are produced from 9.89 g of Li.
In first place, the balanced reaction is:
2 Li + 2 H₂O ⇒ 2 LiOH + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Li= 2 moles
- H₂O= 2 moles
- LiOH= 2 moles
- H₂= 1 mole
The molar mass of each compound is:
- Li= 6.94 g/mole
- H₂O= 18 g/mole
- LiOH= 23.94 g/mole
- H₂= 2 g/mole
By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
- Li= 2 moles× 6.94 g/mole= 13.88 g
- H₂O= 2 moles× 18 g/mole= 36 g
- LiOH= 2 moles× 23.94 g/mole= 47.88 g
- H₂= 1 mole× 2 g/mole= 2 g
Then you can apply the following rule of three: if by reaction stoichiometry 13.88 g of Li produce 47.88 g of LiOH, 9.89 g of Li produce how much mass of LiOH?

Solving:
<u><em>mass of LiOH= 34.12 grams</em></u>
Finalli, 34.12 grams of LiOH are produced from 9.89 g of Li.
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