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3 years ago

What is the length of the hypotenuse of the triangle?

Mathematics

2 answers:

storchak [24]3 years ago

6 0

Answer:

A. 26ft

Step-by-step explanation:

h= 26ft

atroni [7]3 years ago

3 0

Step-by-step explanation:

Hey there!

Here;

ABC is a Right angled triangle.

Taking reference angle as angleA.

Now;

Hypotenuse (h) = AB

Perpendicular (BC)= 24 ft.

Base(AC)= 10 ft.

Now, Using Pythagoras relation;

$h = \sqrt{ {p}^{2} + {b}^{2} }$

Put all values.

$h = \sqrt{ {24}^{2} + {10}^{2} }$

Simplify it.

$h = \sqrt{576 + 100}$

$h = \sqrt{676}$

Therefore, h= 26ft.

ANS: OPTION A.

Hope it helps....

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3 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

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