You have to do 225 plus 125 divided by 2 times 100 and that is your percent
8 for 2 games plus the shoe rentals (15)make it 23 for 2games
for 30$we can bowl a max of 3 games which will cost 27 $
The Intersecting Secant Theorem says
EC × ED = EB × EA
(x+4)(x+4+1) = (x+1)(x+1+11)
(x+4)(x+5)=(x+1)(x+12)
x^2 + 9x + 20 = x^2 + 13 x + 12
8 = 4x
x = 2
Check:
6(7)=42
3(14)=42, good
Answer: 2
Let c=the number of batches for the cookies; b=that for the brownies.
If $P=the profit, then
maximize P=5c+4.5b, subject to the constaints:
3c+4b<=100 (cost)
2c+b<=45 (time)
b,c >=0
The simplest way to find the suitable b & c is
to solve
3c+4b=100
2c+b=45
for b & c
The result is b=13 & c=16
=>
max. p=5(16)+4.5(13)=$138.5
Hope this helps :)
The answer could be
D
but i’m not a 100% sure
