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zloy xaker [14]
3 years ago
14

What LCM of 9 and 21

Mathematics
2 answers:
jeyben [28]3 years ago
5 0

Answer:

63

Step-by-step explanation:

21: 21, 42, 63

9: 9, 18, 27, 36, 45, 54, 63

I am joyous to assist you anytime.

ratelena [41]3 years ago
4 0
The least common multiple of 9 and 21 is 63
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Describe the relationship between bias and variability through an example. Given that the proportion of all Americans that belie
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Answer:

Answers explained below

Step-by-step explanation:

(a) If there is high bias and high variability, the numbers will not be anywhere near the 42 percent value. If I wrote down 10 numbers and they were all completely different from 42, I would know that I have high bias and high variability.

(b) If a certain number of polls have just about the same average, but are nowhere near 42 percent, they have high bias and low variability. For example, 20 percent, but its far from 42 percent.

(c) If there is low bias and high variability, if you list the polls they will have an average around 42 percent. If you average the polls, you'll get 42 percent low bias. The high variability might be 20, 72% 42% 63% 10%

(d) If there is low bias and low variability, all of the polls will be close to 42 percent.

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3 years ago
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From a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. In how many dif
Romashka [77]

Answer:

11,880 different ways.

Step-by-step explanation:

We have been given that from a pool of 12 candidates, the offices of president, vice-president, secretary, and treasurer will be filled. We are asked to find the number of ways in which the offices can be filled.

We will use permutations for solve our given problem.

^nP_r=\frac{n!}{(n-r)!}, where,

n = Number of total items,  

r = Items being chosen at a time.        

For our given scenario n=12 and r=4.

^{12}P_4=\frac{12!}{(12-4)!}

^{12}P_4=\frac{12!}{8!}

^{12}P_4=\frac{12*11*10*9*8!}{8!}

^{12}P_4=12*11*10*9

^{12}P_4=11,880

Therefore, offices can be filled in 11,880 different ways.

     

   

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3 years ago
For homework a student had to complete 15 problems total. If she finished 6 problems in class, what is the ratio of problems she
nexus9112 [7]

Well if the student already finished 6 problems out of 15, there are 15-6 = 9 homework questions she still has to finish.

Still needs to complete: 9.

Already finished: 6

9 : 6.

Simplified: 3 : 2

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3 years ago
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