2 years ago

In trapezoid HJLK, M and N are midpoints of the legs. Find KL. Help me please

1 answer:

4 0

MN is the mid-line of a trapezoid HJLK.
The length of the mid-line of a trapezoid is half of the sum of the lengths of its bases ⇒

(KL + HJ)/2 = MN
(KL + 45)/2 = 28
KL + 45 = 28 * 2
KL + 45 = 56
KL = 56 - 45
KL = 11

You might be interested in

A tire shop had to fill 3 1/2 tires with air. It took a small air

Reika [66]

Answer: 3 seconds

Step-by-step explanation: the pump fills 1 tire per second

7 0

3 years ago

Read 2 more answers

HELP! THIS IS DUE TODAY, and i will mark brainlest!

iren2701 [21]

Answer:

Option 3

Step-by-step explanation:

y=3+x is a straight line that runs through y=3 and x=-3

So your 3rd option here is the one.

3 0

2 years ago

Read 2 more answers

Radius is dash of the diameter

goldfiish [28.3K]

Answer:

Step-by-step explanation:

Radius is 1/2 of the diameter

Diameter is 2 of the radius

6 0

3 years ago

Sam has $\frac{5}{8}$ of a pound of chocolate. If he eats $\frac{1}{3}$ of the chocolate he has, how many pounds of chocolate do

givi [52]

1/3 of 5/8...." of " means multiply
1/3 * 5/8 = 5/24 lbs

3 0

3 years ago

Read 2 more answers

Please help me !!!!!!!!!

lidiya [134]

Answer:

f(-2) = 0

f(1) = 12

f(2) = 5

Step-by-step explanation:

f(-2) will lie in the function $f(x) =x^2 - 4$

$\therefore f( - 2) = {( - 2)}^{2} - 4 = 4 - 4 = 0$

f(1) will lie in the function $f(x) =2x^2 +10$

$\therefore f(1) = 2 {(1)}^{2} + 10 = 2 + 10 = 12$

f(2) will lie in the function $f(x) =5$

$\therefore f(2) = 5$

5 0

2 years ago