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3 years ago

Which statement about organic compounds is true?

Chemistry

1 answer:

blondinia [14]3 years ago

3 0

Answer:

An organic compound typically has at least one carbon–hydrogen or carbon–carbon bond.

Explanation:

It is true that organic compounds have one or more carbon atoms covalently bound to other atoms like hydrogen, oxygen etc

Examples of organic compounds include:

- methane (CH3)

- ethanol (C2H5OH)

In methane, carbon–hydrogen bond is present; while in ethanol both one carbon–hydrogen and carbon-carbon bond is present.

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stiks02 [169]

One correct thging is that there are the same amount of positive and negative atoms

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3 years ago

The variables _______ and ________ affect the gravitational force between objects.

anastassius [24]

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4 years ago

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Which of the following best describes AgCl

vagabundo [1.1K]

Answer: Where are the answers?

Explanation:

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4 years ago

Are the chemical reactions that take place when a battery connected endothermic or exothermic

Vilka [71]

Answer:

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3 years ago

Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling

Reil [10]

Answer:

The boiling point of a 8.5 m solution of Mg3(PO4)2 in water is 394.91 K.

Explanation:

The formula for molal boiling Point elevation is :

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b}$ = elevation in boiling Point

$K_{b}$ = Boiling point constant( ebullioscopic constant)

m = molality of the solution

i = Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

$Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}$

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

i = Van't Hoff Factor = 5

m = 8.5 m

$K_{b}$ = 0.512 °C/m

Insert the values and calculate temperature change:

$\Delta T_{b} = iK_{b}m$

$\Delta T_{b} = 5\times 0.512\times 8.5$

$\Delta T_{b} = 21.76 K$

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

$\Delta T_{b} = T_{b} - T_{b}_{pure}$

$T_{b}_{pure}$ = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0

3 years ago