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3 years ago

C5H6 reacts with itself to form C10H12 according to the following process

1 answer:

swat323 years ago

4 0

When carbon compounds react with themselves to form a larger molecule the process is called polymerization. Specifically addition polymerization. sometimes molecules containing containing carbon to carbon double bonds can join together to form longer chains. The double bond is broken and the electrons in it join to neighboring molecules.

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Write the electrons configuration for an atom of an element whose atomic number is 8

Basile [38]

The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6

6 0

3 years ago

CK-12 Boyle and Charles's Laws if Mrs. Pa pe prepares 12.8 L of laughing gas at 100.0 k Pa and -108 °C and then she force s the

nirvana33 [79]

Answer:

The answer to your question is P2 = 2676.6 kPa

Explanation:

Data

Volume 1 = V1 = 12.8 L Volume 2 = V2 = 855 ml

Temperature 1 = T1 = -108°C Temperature 2 = 22°C

Pressure 1 = P1 = 100 kPa Pressure 2 = P2 = ?

Process

- To solve this problem use the Combined gas law.

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = P1V1T2 / T1V2

- Convert temperature to °K

T1 = -108 + 273 = 165°K

T2 = 22 + 273 = 295°K

- Convert volume 2 to liters

1000 ml -------------------- 1 l

855 ml -------------------- x

x = (855 x 1) / 1000

x = 0.855 l

-Substitution

P2 = (12.8 x 100 x 295) / (165 x 0.855)

-Simplification

P2 = 377600 / 141.075

-Result

P2 = 2676.6 kPa

3 0

3 years ago

Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32

Law Incorporation [45]

Answer:

For a: The standard Gibbs free energy of the reaction is -347.4 kJ

For b: The standard Gibbs free energy of the reaction is 746.91 kJ

Explanation:

Relationship between standard Gibbs free energy and standard electrode potential follows:

$\Delta G^o=-nFE^o_{cell}$ ............(1)

For a:

The given chemical equation follows:

$2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)$

Oxidation half reaction: $Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-$ ( × 2)

Reduction half reaction: $3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)$

We are given:

$n=2\\E^o_{cell}=+1.08V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ$

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

For b:

The given chemical equation follows:

$6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

Oxidation half reaction: $Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-$ ( × 6)

Reduction half reaction: $2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)$

We are given:

$n=6\\E^o_{cell}=-1.29V\\F=96500$

Putting values in equation 1, we get:

$\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ$

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

7 0

3 years ago

Which element has the LEAST metallic character.

timofeeve [1]

Helium would be the least I think

3 0

3 years ago

Read 3 more answers

Polyatomic ion formula for aluminum hydroxide

KonstantinChe [14]

Answer:

Al(OH)3 ? i hope this is what you mean.

7 0

3 years ago

Read 2 more answers