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SpyIntel [72]
3 years ago
8

99 POINTS

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

the function given f(x)=x^3

for 4 units up, just add 4 as a constant

4 units up means, every old value will now be 4 more than previous value. at x=0, y=0 in the transformed curse it should x=0 and y=4, so just add it.

f(x)=x^3+4

for 6 units left,

each old value of y should now occur 6 units before the old value of x i.e. X=x+6

for example, the point (0,0) should occur at (-6,0) in the transformed graph,

hence, f(x)=(x+6)^3

so the final curve is

f(x)=(x+6)^3+4

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What is the average rate of change CAN SOMEONE PLEASE ANSWER THIS QUESTION I WILL BRAINLIEST
Andre45 [30]
<h3>Answer: The average rate of change for both is -2</h3>

=======================================================

Explanation:

The x interval [0,3] is the same as writing 0 \le x \le 3

It starts at x = 0 and ends at x = 3.

The graph shows that x = 0 leads to y = 3. So we have the point (0,3) on the parabola. We also have the point (3,-3) on the parabola.

Let's find the slope of the line through these endpoints.

(x_1,y_1) = (0,3) \text{ and } (x_2,y_2)  = (3,-3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-3 - 3}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

The slope is -2. This is the average rate of change from x = 0 to x = 3.

This is because:

slope = rise/run = (change in y)/(change in x) = average rate of change.

-------------

Now let's find the slope for the table.

Focus on the rows for x = 0 and x = 3. They lead to f(x) = 10 and f(x) = 4 respectively.

We have (0,10) and (3,4) as our two points this time.

(x_1,y_1) = (0,10) \text{ and } (x_2,y_2)  = (3,4)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{4 - 10}{3 - 0}\\\\m = \frac{-6}{3}\\\\m = -2\\\\

We get the same slope as before, so we have the same rate of change.

Notice the change in y (-6) is the same as before. So we could pick any two y values we want as long as there's a gap of 6 between them, and the second y value is smaller than the first.

3 0
2 years ago
Explain how to check multiplication using addition and division ñ. Include an example in your explanation.
ratelena [41]
Addition/Subtraction and. Multiplication/ Division ... So checking one operation with its opposite is a good way to help verify your answer.
5 0
3 years ago
Hellllllp pleas if you want brainliest answer both
Rudik [331]

Answer:

1 is 15

2  the formula of a  trapizod and the are is 35

Step-by-step explanation:

A=a+b2h=2+5 2·10=35

have a good day/night

may i please have a branlliest

3 0
3 years ago
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The amount of air pressure, (PSI) in the spare tire of a certain vehicle (Type A) brought for inspection are normally distribute
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Answer:

f

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3 years ago
The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num
Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

  • C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

n = \dfrac{565}{20} = \mathbf{28.25}

Rounding down to the nearest whole number, we have;

  • The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

  • 20 represents a <u>$20 price per uniform</u>.

3. The 35 in the equation represents an initial <u>flat fee</u>, such as an

ordering or initial fee, which is fixed.

Therefore;

  • The number 35 represent the <u>fixed cost </u>for producing the uniforms

4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

  • The school can purchase <u>10 fewer uniforms</u> at $30 per uniform

Learn more about linear equations here:

brainly.com/question/10452752

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2 years ago
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