Question

99 POINTS

Answer 1

Answer:

the function given $f(x)=x^3$

for 4 units up, just add 4 as a constant

4 units up means, every old value will now be 4 more than previous value. at x=0, y=0 in the transformed curse it should x=0 and y=4, so just add it.

$f(x)=x^3+4$

for 6 units left,

each old value of y should now occur 6 units before the old value of x i.e. X=x+6

for example, the point (0,0) should occur at (-6,0) in the transformed graph,

hence, $f(x)=(x+6)^3$

so the final curve is

$f(x)=(x+6)^3+4$