Your answer is, the number of games each player has played
Generally to measure variability, we use the range, the variance, the standard deviation and inter quartile ranges.
Given is that the averages are same, this implies that the mean of the two data sets are same. Variability can also be measured by the total number of points each player has scored. It can also be determined by the average number of points each player’s team scores per game.
So, correct answer is option B: the number of games each player has played.
Sure hope this helps
Answer:
answer below
Step-by-step explanation:
from the question the
mean = ∑x/n
∑x = 317
n = 16
mean = 19.8125
x x-Ц x-Ц²
19 -0.8125 0.66015625
20 0.1875 0.03515625
19 -0.8125 0.66015625
20 0.1875 0.03515625
18 -1.8125 3.28515625
21 1.1875 1.41015625
17 -2.8125 7.91015625
19 -0.8125 0.66015625
24 4.1875 17.53515625
23 3.1875 10.16015625
21 1.1875 1.41015625
21 1.1875 1.41015625
17 -2.8125 7.91015625
20 -0.8125 0.66015625
20 -0.8125 0.66015625
18 -1.8125 3.28515625
∑(x-Ц)² = 56.44
s.d = 1.9
b.
19.81 + 2*1.9= 23.61
19.81-2*1.9 = 16.01
=
It's 3.01 sorry wrong question please forgive me
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)