Number of possible outcome for tossing N coins = ![2^N](https://tex.z-dn.net/?f=2%5EN)
Solution:
Possible outcomes when tossing one coin = {H, T}
Number of possible outcomes when tossing one coin = 2 ![=2^1](https://tex.z-dn.net/?f=%3D2%5E1)
Possible outcomes when tossing two coins = {HH, HT, TH, TT}
Number of possible outcomes when tossing two coins = 4 ![=2^2](https://tex.z-dn.net/?f=%3D2%5E2)
Possible outcomes when tossing three coins
= {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Number of possible outcomes when tossing three coins = 8 ![=2^3](https://tex.z-dn.net/?f=%3D2%5E3)
Therefore, the sequence obtained is
.
If continue this sequence, we can obtain number of possible outcome for tossing N coins is
.