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yanalaym [24]
3 years ago
9

Hey hey, could someone please help with this (triangle similarity)? Thanks!

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0

Answer:

use mathaway it helps all you have to do is take a picture it it will help u with the steps

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The height in feet of a projectile with an initial
enot [183]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Simplify the radical expression 4 square root 81x^20y^8
Dimas [21]

The simplified expression is 3x^5 y^2

Step-by-step explanation:

The radical expression to simplify is

\sqrt[4]{81x^{20}y^8}

We notice the following:

81=3^4

And using the property

(x^a)^b=x^{a\cdot b}

we can write:

x^{20}=(x^5)^4

y^8 = (y^2)^4

So the argument of the radical can be written as

\sqrt[4]{(3)^4(x^5)^4(y^2)^4} =\sqrt[4]{(3x^5y^2)^4}

And now by using the property

\sqrt[n]{a^n}=a

We find:

\sqrt[4]{(3x^5y^2)^4}=3x^5 y^2

Learn more about simplification of expressions:

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4 0
3 years ago
Read 2 more answers
URGENT !!! 25 POINTS AND BRAINIEST FOR CORRECT ANSWER!!!
Ne4ueva [31]

Given a polynomial p(x) with leading coefficient a and solutions x_1,x_2,\ldots,x_n, we have

p(x)=a(x-x_1)(x-x_2)\ldots(x-x_n)

That's why we have to find the solutions first. We complete the square by adding 3 to both sides:

x^2-2x-2=0 \iff (x^2-2x-2)+3=3 \iff x^2-2x+1=3 \iff (x-1)^2=3

From here, we continue by taking the square root of both sides:

x-1=\pm 3 \iff x=1\pm\sqrt{3}

So, the two solutions are

x_1=1+\sqrt{3},\quad x_2=1-\sqrt{3}

Which yields the factorization

x^2-2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})

3 0
3 years ago
HELP!!!!!??!!!???????????!!!!!!
loris [4]

Answer:

FALSEE???

Step-by-step explanation:

I HAVE NO IDEA GIRL- IM DOING THAT QUESTION RN TO THO -

3 0
2 years ago
I don't get the problem to 6j-3 for j=4
Anit [1.1K]

Answer:

6×4-3=21

Step-by-step explanation:

you replace the j by 4 so you multiply the 6 by 4 and then proceed to subtract three getting 21

6 0
3 years ago
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