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3 years ago

Hey hey, could someone please help with this (triangle similarity)? Thanks!

Mathematics

1 answer:

Akimi4 [234]3 years ago

4 0

Answer:

use mathaway it helps all you have to do is take a picture it it will help u with the steps

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The height in feet of a projectile with an initial

enot [183]

Answer:

thus is what i learnd as a baby 64CK NI>GGA DI PSY SH :]

Step-by-step explanation:

6 0

3 years ago

Simplify the radical expression 4 square root 81x^20y^8

Dimas [21]

The simplified expression is $3x^5 y^2$

Step-by-step explanation:

The radical expression to simplify is

$\sqrt[4]{81x^{20}y^8}$

We notice the following:

$81=3^4$

And using the property

$(x^a)^b=x^{a\cdot b}$

we can write:

$x^{20}=(x^5)^4$

$y^8 = (y^2)^4$

So the argument of the radical can be written as

$\sqrt[4]{(3)^4(x^5)^4(y^2)^4} =\sqrt[4]{(3x^5y^2)^4}$

And now by using the property

$\sqrt[n]{a^n}=a$

We find:

$\sqrt[4]{(3x^5y^2)^4}=3x^5 y^2$

Learn more about simplification of expressions:

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4 0

3 years ago

Read 2 more answers

URGENT !!! 25 POINTS AND BRAINIEST FOR CORRECT ANSWER!!!

Ne4ueva [31]

Given a polynomial p(x) with leading coefficient $a$ and solutions $x_1,x_2,\ldots,x_n$ , we have

$p(x)=a(x-x_1)(x-x_2)\ldots(x-x_n)$

That's why we have to find the solutions first. We complete the square by adding 3 to both sides:

$x^2-2x-2=0 \iff (x^2-2x-2)+3=3 \iff x^2-2x+1=3 \iff (x-1)^2=3$

From here, we continue by taking the square root of both sides:

$x-1=\pm 3 \iff x=1\pm\sqrt{3}$

So, the two solutions are

$x_1=1+\sqrt{3},\quad x_2=1-\sqrt{3}$

Which yields the factorization

$x^2-2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

3 0

3 years ago

HELP!!!!!??!!!???????????!!!!!!

loris [4]

Answer:

FALSEE???

Step-by-step explanation:

I HAVE NO IDEA GIRL- IM DOING THAT QUESTION RN TO THO -

3 0

2 years ago

I don't get the problem to 6j-3 for j=4

Anit [1.1K]

Answer:

6×4-3=21

Step-by-step explanation:

you replace the j by 4 so you multiply the 6 by 4 and then proceed to subtract three getting 21

6 0

3 years ago