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nekit [7.7K]
4 years ago
13

What are the steps for using a compass and straightedge to construct a line through point P that is parallel to line m? A horizo

ntal line m and a point P are drawn. The point P is above the horizontal line m. Drag the steps and drop them in order from start to finish.

Mathematics
2 answers:
seraphim [82]4 years ago
7 0

Answer:

Here, m is a line and we have to find the draw parallel line of line of m through a point P with the help of straightedge and compass,

The correct order of steps for constructing a line through point P that is parallel to line m are as follows,

Step 1 : Use the straightedge to draw a line n that passes through P and intersect line m, lebel the point of intersection as X,

Step 2 : Place the point of the compass on point X and draw an arc that intersect line m and n, label the intersection point A and B,

Step 3 : Without changing the width of the compass opening, place the point of compass on point P and draw an arc that intersect line n label the intersection point as C,

Step 4 : Place the point of compass on point A and open it to the width of AB,

Step 5 : With the compass opening set the width of AB, place the point of the compass On point C and draw an arc that intersects the arc that was drawn from point P lebel the intersection of arc as point Y,

Step 6 : Use the straightedge to draw PY

kodGreya [7K]4 years ago
6 0

Answer:

Here's the list of the following sequence in the right order for you (I took the test myself and got this whole sequence right)

1. Use the straightedge to draw a line n that passes through <em>P</em> and intersects line <em>m</em>. Label the point of intersection as point <em>X</em>.

2. Place the point of the compass on point <em>X</em> and draw an arc that intersects lines <em>m</em> and <em>n</em>. Label the intersections as points <em>A</em> and <em>B</em>.

3. Without changing the width of the compass opening, place the point of the compass on point <em>P</em> and draw an arc that intersects line <em>n</em>. Label the intersection as point <em>C.</em>

4. Place the point of the compass on point <em>A</em> and open it to width <em>AB</em>.

5. With the compass opening set to width <em>AB</em>, place the point of the compass on point <em>C</em> and draw an arc that intersects the arc that was drawn from point <em>P</em>. Label the intersection of the arcs as point <em>Y</em>.

6. Use the straightedge to draw <em>line PY</em>.


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<u>Step-by-step explanation</u>:

<u>Given that,</u>

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<u>Let us assume,</u>

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<u>Forming the equation to solve x and y values :</u>

  • The total number of softball ordered = 120
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x + y = 120  -------(1)

2.5x + 3.5y = 350   --------(2)

<u>Multiply eq(1) by 2.5 and subtract eq(2) from eq(1)</u>,

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-<u>(2.5x +3.5y = 350)</u>

  <u>        -1y     =  -50</u>

Therefore the value of y = 50.

The number of 12-inch softball is 50.

<u>Substitute y=50 in eq(1),</u>

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x = 120-50

x = 70

The number of 11-inch softball is 70.

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