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nekit [7.7K]
3 years ago
13

What are the steps for using a compass and straightedge to construct a line through point P that is parallel to line m? A horizo

ntal line m and a point P are drawn. The point P is above the horizontal line m. Drag the steps and drop them in order from start to finish.

Mathematics
2 answers:
seraphim [82]3 years ago
7 0

Answer:

Here, m is a line and we have to find the draw parallel line of line of m through a point P with the help of straightedge and compass,

The correct order of steps for constructing a line through point P that is parallel to line m are as follows,

Step 1 : Use the straightedge to draw a line n that passes through P and intersect line m, lebel the point of intersection as X,

Step 2 : Place the point of the compass on point X and draw an arc that intersect line m and n, label the intersection point A and B,

Step 3 : Without changing the width of the compass opening, place the point of compass on point P and draw an arc that intersect line n label the intersection point as C,

Step 4 : Place the point of compass on point A and open it to the width of AB,

Step 5 : With the compass opening set the width of AB, place the point of the compass On point C and draw an arc that intersects the arc that was drawn from point P lebel the intersection of arc as point Y,

Step 6 : Use the straightedge to draw PY

kodGreya [7K]3 years ago
6 0

Answer:

Here's the list of the following sequence in the right order for you (I took the test myself and got this whole sequence right)

1. Use the straightedge to draw a line n that passes through <em>P</em> and intersects line <em>m</em>. Label the point of intersection as point <em>X</em>.

2. Place the point of the compass on point <em>X</em> and draw an arc that intersects lines <em>m</em> and <em>n</em>. Label the intersections as points <em>A</em> and <em>B</em>.

3. Without changing the width of the compass opening, place the point of the compass on point <em>P</em> and draw an arc that intersects line <em>n</em>. Label the intersection as point <em>C.</em>

4. Place the point of the compass on point <em>A</em> and open it to width <em>AB</em>.

5. With the compass opening set to width <em>AB</em>, place the point of the compass on point <em>C</em> and draw an arc that intersects the arc that was drawn from point <em>P</em>. Label the intersection of the arcs as point <em>Y</em>.

6. Use the straightedge to draw <em>line PY</em>.


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Answer: d=12

Step-by-step explanation:

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Multiply both parts of the equation by 8:

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8 0
1 year ago
The volume of the cell phone is 75 cubic centimeters. Write and solve an equation to find the height of the cell phone. Round yo
prohojiy [21]

Answer:

Equation: Height = \frac{75}{Area}

Step-by-step explanation:

<em>The question is incomplete as the dimension of the phone was not given.</em>

<em>However, the following explanation will guide you</em>

Given

Volume = 75\ in^3

Required

Determine the Height

Volume is calculated as thus;

Volume = Area * Height

Substitute 75 for Volume

75= Area * Height

Divide through by Area

Height = \frac{75}{Area}

<em>The above represent the equation to solve for Height</em>

<em>To solve for height, we need the dimension of the phone or the area.</em>

Take for instance; the length and width of the phone is 5 by 5 inches;

The height would be:

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Does anyone know how to solve this?
Olegator [25]

m=70/2=35

n=(360-70*2)/2=110

6 0
2 years ago
Read 2 more answers
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