Answer:

Step-by-step explanation:
The unit vector for a nonzero vector, say u, in the direction of u is given by:
û =
---------------(i)
Where;
|u| = magnitude of vector u
From the question;
u = (4, -4)
First let's calculate the magnitude of u as follows;
|u| = 
|u| = 
|u| =
= 
Now, substitute u and |u| into equation (i) as follows;
û = 
û = 
û = 
Therefore, the unit vector is 
Idk im just tryna complete a challenge lol
Answer:
Step-by-step explanation:
y=3√x
domain : all real values≥0
Quadratic is in the form
ax^2+bx+c=0
so distribute and stuff and simplify
remember
a(b+c)=ab+ac
(x+2)^2+5(x+2)-6=0
remember order of opertaions
(x+2)(x+2)+5(x+2)-6=0
x^2+4x+4+5x+10-6=0
add like terms
x^2+9x+8=0
Answer:
-3, -4, -5, -6, -7, -8
Step-by-step explanation:
Im not sure if that is what you are looking for or if you want x ≤ -3 and x ≥ -8