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frutty [35]
3 years ago
12

Find the sum of the geometric series: 32 - 8 + 2 - 1/2 +...

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0
Time to work it out 
32 - 8 + 2 - 1/2
32 - 8 + 2 = 26
now you have
-1/2 + 26 
so we convert 26 to fraction form to subtract 
26/1 - 1/2
we must find the common denominator
52/2 - 1/2
51/2
fifty-one over 2 (fraction) is your answer! :)
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Is 45 a multiple of 4? Explain your answer (20 point offer)
SSSSS [86.1K]

Answer:

The multiples of 4 are: 4,8,12,16,20,24,28,32,36,40,44,.

Step-by-step explanation:

so no

4 0
3 years ago
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Point E is the midpoint of AB and point F is the midpoint of CD .
Gwar [14]

Answer:

# AB is bisected by CD

# AE = 1/2 AB

# CE + EF = FD

Step-by-step explanation:

* Lets talk about the mid point

- The mid-point of a segment is divided the segment into two

  equal parts

- The figure has line segment AB

- E is the mid-point of AB

∴ E divides the line segment AB into two equal parts

∴ AE = EB

∴ AE = 1/2 AB ⇒ (1)

- Any line passes through the point E will bisects the line segment AB

∴ AB is bisected by CD ⇒ (2)

∵ F is the mid-point of CD

∴ F divides the line segment CD into two equal parts

∴ CF = FD

∵ Point E lies on CF

∴ CE + EF = CF

∵ CF = FD

∴ CE + EF = FD ⇒ (3)

* There are three statements must be true (1) , (2) , (3)

# AB is bisected by CD

# AE = 1/2 AB

# CE + EF = FD

6 0
3 years ago
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Can someone help me?​
miss Akunina [59]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
Someone please help me find x
a_sh-v [17]
So for a tangent and a secant, you multiply x^2 (since it’s a tangent you square it) and test that equal to 6(6+12) so now you have x^2=6(6+12). solve for X to get sqrt(108) or 10.4

the equation is — tan^2=outside x whole thing

remember to ADD the entire secant (so add 6 plus 12) don’t multiply them (6x12)

x^2=6(6+12)
x^2=6(18) OR x^2=36+72
x^2=108
x=sqrt(108) OR x=10.4
4 0
2 years ago
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Please help meeeeeeeeeeeee<br><br><br>directions: use substitution to solve the solution
dimaraw [331]

Answer:

(-3, 13)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -4x + 1

11y = x + 146

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                   11(-4x + 1) = x + 146
  2. Distribute 11:                                                                                                     -44x + 11 = x + 146
  3. [Addition Property of Equality] Add 44x on both sides:                              11 = 45x + 146
  4. [Subtraction Property of Equality] Subtract 146 on both sides:                  -135 = 45x
  5. [Division Property of Equality] Divide 45 on both sides:                             -3 = x
  6. Rewrite/Rearrange:                                                                                             x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                                  y = -4x + 1
  2. Substitute in <em>x</em>:                                                                                                   y = -4(-3) + 1
  3. Multiply:                                                                                                           y = 12 + 1
  4. Add:                                                                                                                      y = 13
3 0
2 years ago
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