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3 years ago

Will the value of the expression 20−x increase, decrease, or stay the same as x increases? Explain.

Mathematics

1 answer:

asambeis [7]3 years ago

7 0

Answer:

Step-by-step explanation:

Given the expression 20 - x.

The value of x determines if the value of the expression would increase, decrease or stay the same. When the value of x decreases, the value of 20 - x increases. When the value of x increases, the value of 20 - x decreases. And when the value of x does not change, 20 - x remains the same.

When greater values of x is subtracted from 20, you will have lower value left. Therefore, as x increases, the value of the expression 20 - x will decrease.

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4(x + 3) = 3(3x - 1)

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X=3
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Please help. Felipe is planning a party. He has $50 to spend on sandwiches That cost $2.50 Per person , $25 to spend on drinks t

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Answer:

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3 years ago

The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.

nignag [31]

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

$x^2+6x=-9$

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

$x^2+6x+9=-9+9$

The reason we do this is to create a perfect square binomial on the left:

$(x+3)^2=0$ (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

$(x+3)^2+0=y$

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

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3 years ago

Find the minimum point for the function f(x) = |2x - 1| (0, ½) (½, 0) (0, -½) (-½, 0)

torisob [31]

Minimum point of an absolute value function is when f(x) = 0
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Minimum point is (1/2, 0)

6 0

3 years ago

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) The Lowest amount of sale made by Latasha in one month

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

For Latasha :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

For Kayla :

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

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2 years ago