1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bixtya [17]
4 years ago
11

Calculate the distance between the pairs of coordinates, and classify them according to the distance between them. 

Mathematics
1 answer:
Neporo4naja [7]4 years ago
6 0

The true key to geometry is when we stop being concerned with distance and do everything with squared distances. The square roots magically melt away.


The squared distance between two points (a,b) and (c,d) is given by the Pythagorean Theorem:


D^2 = (a-c)^2 + (b-d)^2


Apparently some of our squared distances will be 10 and some will be 29. We can pretty much eyeball which is which, but let's work them out:


(3,4),(2,1): \quad D^2=(3-2)^2+(4-1)^2=1+9=10


(3,7),(5,2): \quad D^2=(3-5)^2+(7-2)^2=4+25=29


(5,2),(3,3): \quad D^2=(5-2)^2+(3-2)^2=10


(-2,3),(1,2): \quad D^2=(-2 - 1)^2 + (3-1)^2 = 10


(-4,-2),(-3,1): \quad D^2=(-4 - -3)^2 + (-2 - 1)^2=10


(4,-1),(-1,1): \quad D^2=(4 - -1)^2 + (-1 - 1)^2 = 29


With integer coordinates we'll always get a squared distance that's the sum of two squares, but it won't always be 10 or 29.



You might be interested in
1-What is the sum of the series? ​∑j=152j​ Enter your answer in the box.
tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

1)

∑\left \ {{5} \atop {j=1}} \right. 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

  =  2 + 4 + 6 + 8 + 10

∑ = 30

2)

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑\left \ {{4} \atop {k=1}} \right. 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

  = 2(1) + 2(4) + 2(9) + 2(16)

  =  2 + 8 + 18 + 32

∑ = 60

∑\left \ {{4} \atop {k=1}} \right. (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

  = (2)² + (4)² + (6)² + (8)²

  = 4 + 16 + 36 + 64

∑ = 120

∑\left \ {{4} \atop {k=1}} \right. (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

  = (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

  = (4-4) + (16-4) + (36-4) + (64-4)

  = 0 + 12 + 32 + 60

∑ = 104

∑\left \ {{4} \atop {k=1}} \right. 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

  = 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

  = (2-4) + (8-4) + (18-4) + (32-4)

  = -2 + 4 + 14 + 28

∑ = 44

3)

∑\left \ {{6} \atop {k=3}} \right. (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)  

  = (6-10) + (8-10) + (10-10) + (12-10)

  = -4 + -2 + 0 + 2  

∑ = -4

4)

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1  = 1/2

1/16/1/8 = 1/16 * 8/1  = 1/2

1/32/1/16 = 1/32 * 16/1  = 1/2

1/64/1/32 = 1/64 * 32/1  = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

ar^{n-1} = 1(\frac{1}{2})^{n-1}

So the answer that represents the series in sigma notation is:

∑\left \ {{7} \atop {j=1}} \right. (\frac{1}{2})^{j-1}

5)

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So  

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑\left \ {{5} \atop {j=1}} \right. (2j−5)

6 0
4 years ago
Please help! (I'll give brainliest to the first right answer)
Zanzabum

Answer:

Step-by-step explanation:

5 0
3 years ago
Replacing only the minimum value in a data to a smaller number will change the median
irakobra [83]
This is false my dude.
5 0
3 years ago
Read 2 more answers
-4/5 + 4/5<br> Please I need the grade
KATRIN_1 [288]

Answer:

0 hope it helps ok bye have a good grade

8 0
3 years ago
Read 2 more answers
And an electronics warehouse ships TVs and DVD players to retailers all throughout the United States. The weight of three televi
vodomira [7]
X= weight of TV
y= weight of CD

3x+5y= 62.5
3x+ 2y= 52
You can either solve for a variable, or eliminate a variable by subtracting the second equation from the first:

3x + 5y = 62.5
-(3x+2y = 52)
0 + 3y = 10.5, so y = 10.5/3 or 3.5.

Now plug y= 3.5 back into any equation to get x:

3x + 5(3.5) = 62.5
3x + 17.5 = 62.5
3x = 45
x = 15
Always check work. Both equations should be true for x=15, y= 3.5
4 0
3 years ago
Other questions:
  • 28,082÷4,347 I need help
    10·1 answer
  • There are 5/7 as many barrettes as hair ties in Sasha's hair supplies. There are 5/8 barrettes as hair bands in her supplies. Wh
    13·2 answers
  • An electrician
    9·2 answers
  • The volume of a cylinder is 169 in.3 and the height of the cylinder is 1 in. What is the radius of the cylinder?
    5·1 answer
  • The circumcenter of a triangle is equidistant from the ____________ of the triangle.
    13·1 answer
  • IF CORRECT I WILL GIVE BRAINLYIST
    14·2 answers
  • PLS HELP I NEED IT I will give u points
    5·1 answer
  • E =mc^2 , solve for m
    9·1 answer
  • What is the solution? 4p – 12 = 8 + 4p + 5p<br> a. 16<br> b. 6<br> c. -5<br> d. -4
    10·2 answers
  • HELP PLEAS EI GIVE BRAINLISt
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!