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Vesnalui [34]
3 years ago
9

E =mc^2 , solve for m

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

e = m {c}^{2}  \\ m =  \frac{e}{ {c}^{2} }  \\ thank \: you

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Jeffrey went to the movies with his friends. The tickets cost $8.50 each for students and they spent $15.00 altogether at the co
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Answer:

4 people

Step-by-step explanation:

Let's first write an equation.

We want to find the number of tickets t

The total was $49 so our equation will equal $49 and they spent $15 in snacks so on the other side of the eqaution we have to add $15, on the same side as the snacks we need to add in the cost of tickets, which is $8.50 multiplies by t, or the total number of tickets.

$49 = $8.50t + $15

Solve for t, first subtract $15 from both sides.

$49 - $15 = $8.50t

$34 = $8.50t   Divide both sides by $8.50

$34/$8.50 =  $8.50t/$8.50  

$34/$8.50 = t

4 = t

4 tickets meaning 4 people went.

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How many lines of symmetry does the picture have? <br> A. 2<br> b. 3<br> c. 0<br> d.1
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Please I’ve attached the question can you help me
Andreyy89

Answer:

1. <em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. <em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. D. I, II and III.

Step-by-step explanation:

U = {21, 22, 23, ..., 64}

A prime number is a number that can be divided only by 1 and itself.

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B = {24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

C = {6, 10, 12, 15, 20, 30, 60}

1. Find <em>n</em>[(A U B) - C]

<em>n</em>(A U B) = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63}

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63} - {6, 10, 12, 15, 20, 30, 60}

Since only 30 and 60 are common to <em>n</em>(A U B) and C, we therefore remove them it and have:

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. Find <em>n</em>[(A - B) U C]

To get <em>n</em>(A - B) we remove all the elements of B in A. Since there are no common elements between A and B, we therefore have:

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

C = {6, 10, 12, 15, 20, 30, 60}

Therefore, we have:

<em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. Which of the following is/are true?

I. A ∩ B = A ∩ C

A ∩ B = ∅

A ∩ C = ∅

Therefore, A ∩ B = A ∩ C is true.

II. A - B = A - C

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

A - C = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

Therefore, A - B = A - C is true.

III. A ∩ (B ∪ C) = ∅

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B U C = {6, 10, 12, 15, 20, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

Therefore, A ∩ (B ∪ C) = ∅ is true.

Therefore, the correct option is D i.e. I, II and III are true.

4 0
3 years ago
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