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shepuryov [24]
3 years ago
12

Replacing only the minimum value in a data to a smaller number will change the median

Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

Solution:

we have been asked to find that whether the given statement is True or False.

Replacing only the minimum value in a data to a smaller number will change the median....FALSE

As we know the median is caluclated by arranging the given numbers in ascending/descending order. The we choose the middle one as a median if total number of numbers are odd. But if toal numbers of numbers are even then we take the average of the middle two and that average is the median.

So if we you are going add a number in the given set of numbers then surely the median is going to change, irrespective of the vaue of the number.

Hence the given statement is  False.

irakobra [83]3 years ago
5 0
This is false my dude.
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Answer:

24 eight-digit code.

Step-by-step explanation:

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In total there are Eight (8) numbers and 3 frequent number ( which are 0, 2, 4 )

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

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Let us try to find out \angle E and \angle DFE. After that we will compare them.

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\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

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8 0
3 years ago
PIUWawilities
blondinia [14]

Answer:

23.44%

Step-by-step explanation:

The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5

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So the required probability =  0.01116 * 21

= 0.2344 or 23.44%.

3 0
3 years ago
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