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3 years ago

Solve the triangle A=52degrees, b=10, c=7

2 answers:

6 0

Let the triangle is ABC

$a^2=b^2+c^2-2bc*cos(A)=100+49-(2*10*7)(cos52)\\a=7.29$

$c^2=b^2+a^2-2ab*cos(C)\\
49=100+53.16-(2*10*7.29)(cos(C))\\~\\C=49.35$

A+B+C =180
52+B+49.35=180

B=78.65

Talja [164]3 years ago

4 0

Answer:

Step-by-step explanation:

Given that a triangle has two sides, A= 52 deg, b=10, c=7

Use cosine law to get

$a = \sqrt{b^2 + c^2 - 2bccos(A)} = 7.92511$

$\∠B = arccos( \frac{a^2 + c^2 - b^2}{2ac} = 1.46418 rad = 83.891 degrees= 83°53'28"∠C = arccos( \frac{a^2 + b^2 - c^2}{2ab} = 0.76985 rad = 44.109° = 44°6'32"$

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13^-11x13^16x13^-3x13^^4x13^-5

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4 years ago

A new building is being constructed at UT Austin. It is 200 feet tall, and has a

Mariana [72]

Answer:

Walkway is 3 feet wide.

Step-by-step explanation:

Given:

Length of the building is 150 ft

width of the building is 100 ft

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Solution:

Length of the total area will be = length of the building + width of walkway from 2 sides = $150 +2x$

Width of the total area will be = width of the building + width of walkway from 2 sides = $100 +2x$

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$(150+2x)\times(100+2x)=16536\\15000+300x+200x+4x^2=16536\\500x+4x^2=16536-15000\\4(125x+x^2)=1536\\125x+x^2= \frac{1536}{4}=384\\$

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Now solving for both equation we get.

$x+128=0\\x=-128\\x-3=0\\x=3$

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3 years ago

Read 2 more answers

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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3 years ago

How do i do these using the following functions

attashe74 [19]

Step-by-step explanation:

(f+g)(x) means f(x) + g(x).

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4 years ago

Help me please!!!!!! It’s math btw.

FrozenT [24]

1. The 5/65 can be simplified, the a³ moves to the denominator, and bc is canceled from the numerator and denominator.
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$\frac{10a^3bc^2}{125a^4bc} = \frac{2c}{25a}$

3. The 65/5 simplifies, the a³ moves to the numerator, and bc is canceled from the numerator and denominator.
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5. The 10/130 simplifies, the b² cancels out in the numerator and denominator, the $a^4$ moves to the numerator, and the $c^4$ moves to the numerator.
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I believe the only expression that simplifies to $\frac{c}{13a}$ is the first one.

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3 years ago