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3 years ago

The pyramid has a volume of 972 cubic inches. What are the dimensions of the pyramid?

2 answers:

8 0

Hi there! :) The answer I got is

Base Length: 12

Base Width: 5

Pyramid Height: 48.6

( I am sorry if it is the answer is wrong. If it is right mark as Brainliest!:) Thank you!;) )

Hope I helped! :D

notka56 [123]3 years ago

4 0

Yep he is right. =) sorry i couldn't get here in time.

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Find the value of x. ladidada i need 20 characters

Nonamiya [84]

X = 3

20 characterssssssssssss

5 0

4 years ago

Scientists were studying a rare species of parrot. They went to a forest in the year

Brrunno [24]

Answer:

$P(t) = 608(1.5)^{t}$

Step-by-step explanation:

The number of parrots in t years after 2010 can be modeled by the following function:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the number of parrots in 2010 and r is the growth rate, as a decimal.

608 parrots in the forest in 2010.

This means that $P(0) = 608$

Then

$P(t) = 608(1+r)^{t}$

When the scientists went back 5 years later, they found 4617 parrots.

This means that $P(5) = 4617$

We use this to find 1 + r. So

$P(t) = 608(1+r)^{t}$

$4617 = 608(1+r)^{5}$

$(1+r)^{5} = \frac{4617}{608}$

$1 + r = \sqrt[5]{\frac{4617}{608}}$

$1 + r = 1.5$

$P(t) = 608(1.5)^{t}$

8 0

3 years ago

Emily and Kate were at a cheerleading competition this fall.They cheered 12 rounds. Each round lasted 8.24 minutes. Calculate th

trapecia [35]

Answer:

98.88

Step-by-step explanation:

Given: They cheered 12 rounds. Each round = 8.24

To find the total number, multiply how much one round is with the total number of rounds.

8.24

× 12

-----------

1648

+ 8240

----------

98.88

Each girl cheered 98.88 minutes. If you need this estimated, the answer would be 99 minutes.

4 0

3 years ago

Graph the equation y= x^2 - 2x - 8 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Vanyuwa [196]

Answer:

I'm not so sure about this one so sorry if this is wrong

Step-by-step explanation:

7 0

3 years ago

I don’t understand this

Oxana [17]

You have to multiply whats outside the parenthesis with everything that is inside, so

$x^{-3}y^0.(x^2-3x^5y^4)$

$x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4$

Multiplication of same bases we sum the exponents

$x^{-3+2}y^0-3x^{-3+5}y^{0+4}$

$x^{-1}.1-3x^2y^4$

$x^{-1}-3x^2y^4$

Alternative B.

7 0

3 years ago