Your numbers are .17 and .165 meters
Let me explain each digit value:
Lets start with .17
Decimals are like whole numbers where each placement has a digit value
.1 is the tenths place
.07 is the hundredths place
Lets turn to .165
.1 is the tenths place
.06 is the hundredths place
.005 is the thousandths place
When seeing which decimal is larger, go along the tenths place and move along.
So as you can see
, .17 and .165 start with .1 so you can't see which is bigger by this. Now move on to the next digit. Which is larger? .17 or .16? As you should know, 7 is bigger than 6 so that means .17 is larger
Answer: .17 meters is larger than .165 meters
Check the picture below.
so the perimeter of the kite is x+x+y+y, namely 2x + 2y.
![\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=\sqrt{8^2+15^2}\implies x=\sqrt{289}\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7Bx%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B15%7D%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20x%3D%5Csqrt%7B8%5E2%2B15%5E2%7D%5Cimplies%20x%3D%5Csqrt%7B289%7D%5Cimplies%20%5Cboxed%7Bx%3D17%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=\sqrt{8^2+4^2}\implies y=\sqrt{80}\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7By%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B8%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B4%7D%5C%5C%20%5Cend%7Bcases%7D%5Cimplies%20y%3D%5Csqrt%7B8%5E2%2B4%5E2%7D%5Cimplies%20y%3D%5Csqrt%7B80%7D%5Cimplies%20%5Cboxed%7By%5Capprox%208.94%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%202x%2B2y%5Cimplies%202%2817%29%2B2%288.94%29%5Cimplies%2051.88%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%20more%7D%7D%7B51.9%7D)
(9.95x2)+14.95)=34.85
34.85x.06=2.09
34.85+2.09=36.94
so the total cost is 36.94$
Answer: 6 ways
there are 6 ways to move from one corner of a cube to the diagonally opposite corner in three moves
Step-by-step explanation:
Given that;
-It's restricted to three moves.
-It has to move from one diagonal to its opposite diagonal.
-it can only move through the edges.
Hence, in the first move.
We have three(3) different options that is three different possible moves that can lead us to the final destination.
The second move.
We have two (2) different possible moves each
The last move
We have just one(1) possible move.
To get the total possible ways, we will multiply the possible options for each move.
Move 1 = 3 options
Move 2 = 2 options each
Move 3 = 1 option each
3 × 2 × 1 = 6 ways
