Can you show the whole question
First, we need to transform the equation into its standard form (x - h)²=4p(y - k).
Using completing the square method:
y = -14x² - 2x - 2
y = -14(x² + 2x/14) - 2
y = -14(x² + 2x/14 + (2/28)²) -2 + (2/28)²
y = -14(x + 1/14)² - 391/196
-1/14(y + 391/196) = (x + 1/14)²
This is a vertical parabola and its focus <span>(h, k + p) is (-1/14, -391/196 + 1/56) = (-1/14, -775/392).
Or (-0.071,-1.977).</span>
<span>Just graph the function up to and/or including the points indicated.
- if you have a piecewise function defined as y=x when x < 0
y=-x when x >=1
You would graph y=x from the negative direction up to 0 (but leaving an open circle on 0 because the function is not defined there
Then start at point 1 (this time with a closed circle because y=-x is defined at 1, and graph y=-x.</span>
Greetings from Brasil...
We have to remember 2 details:
→ When X = 0, the function intersects the Y axis
→ When Y = 0, the function intersects the X axis
So
1: X = 0
Y = X + 5
Y = 0 + 5
Y = 5
X = 0 and Y = 5 ⇔ (0; 5)
2: Y = 0
Y = X + 5
0 = X + 5
X = - 5
Y = 0 and X = - 5 ⇔ (- 5; 0)
Then the point at which the graph intersects the X and Y axis will be
(0; 5) and (- 5; 0)
Answer:
b
Step-by-step explanation:
