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nevsk [136]
4 years ago
6

6x + 8 - 13x + 10 = 4 - 6x - 11 + 4x

Mathematics
1 answer:
Pavlova-9 [17]4 years ago
8 0

Answer:

5

Step-by-step explanation:

6x+8-13x+10=4-6x-11+4x

-7x+18=-2x-7

    -18       -18

-7x=-2x-25

+2x  +2x

-5x=-25

/-5   /-5

x=5

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Figure A maps to figure B with a scale factor of 1 1/2.<br> What is the value of x?
aalyn [17]

Answer:

x = 6/2 = 3

Step-by-step explanation:

This is a dilation. A dilation is a change in size, whether it is an enlargement or reduction.

The scale factor is how much the enlargement is.

The side of Figure A is 2.

So we must multiply 2 ⋅ 1 1/2.

2 ⋅ 1 1/2 (3/2) = 6/2

6/2 is equal to 3.

Therefore, the value of x in Figure B is 3.

8 0
3 years ago
Evaluate the expression for y = -7.<br><br> 2y = __
vivado [14]

Answer:

2y=-14

Step-by-step explanation:

If y=-7 and you multiply y by 2, you do the same thing to both sides and get -7 × 2 = -14

5 0
3 years ago
This year benny is 12 years old and his mom is 48 years old what percent of his mom age is benny
Drupady [299]

Answer:

Hello! Benny is 25%of his Moms age

Step-by-step explanation:

7 0
3 years ago
Consider quadrilateral BCEF inscribed in circle A. Diagonals EB and CF intersect at point D. Select all the statements that are
Elena L [17]

Answer:

m\angle ECB+m\angle EFB=180

m\angle CDB\cong m\angle EDF

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

m\angle ECB+m\angle EFB=180

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

m\angle CDB\cong m\angle EDF

Also sum of angles in triangle CBD is 180°.

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Brilliant_brown [7]

-2<em>x</em> + 6<em>y</em> = -38

3<em>x</em> - 4<em>y</em> = 32

To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.

3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114

2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64

Add the equations.

-6<em>x </em>+ 18<em>y</em> = -114

6<em>x</em> - 8<em>y</em> = 64

+_____________

0 + 10<em>y</em> = -50

10<em>y</em> = -50

<em>y</em> = -5

Substitute -5 for y into one of the original equations to find x.

3<em>x</em> - 4<em>y</em> = 32

3<em>x</em> - 4(-5) = 32

3<em>x</em> + 20 = 32

3<em>x</em> = 12

<em>x</em> = 4

Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.

-2<em>x</em> + 6<em>y</em> = -38

-2(4) + 6(-5) = -38

-8 - 30 = 38

38 = 38


3<em>x</em> - 4<em>y</em> = 32

3(4) - 4(-5) = 32

12 + 20 = 32

32 = 32

Answer:

<em>x</em> = 4 and <em>y</em> = -5; (4, -5).

8 0
3 years ago
Read 2 more answers
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