Answer:
We have 40% antifreeze and 70% antifreeze and we need to make 240 liters of 64% antifreeze.
We set up 2 equations where "f" is the 40 % and "s" is the 70%
A) f + s = 240
B) .40f + .70s = (.64 * 240) (or 153.6)
To solve both equations we multiply A) by -.40
A) -.40 f - .40 s = -96.00 then we add this to B)
B) .40f + .70s = 153.60
.30s = 57.6
s = 192
f = 48
48 liters of 40% = 19.20 liters of antifreeze
192 liters of 70% = 134.40 liters of antifreeze
That equals 153.60 liters of antifreeze in a TOTAL liquid amount of 240 liters.
Double Check
153.60 / 240 = 64% antifreeze.
Step-by-step explanation:
So throwing a die hs 6 choices
26 letters
not sure what the points are
if you want to list all of the options then
multipliy 6 by 26
6 times 26=156
so 156 spaces
Answer:
Equations 1 & 3 are correct.
Explanation:
Equation 2's actual answer is -8, and Equation 4's actual answer is positive 7.
Answer:

Step-by-step explanation:

The number of rows in the arena is 26
<h3>How to determine the number of rows?</h3>
The hockey arena illustrates an arithmetic sequence, and it has the following parameters:
- First term, a = 220
- Sum of terms, Sn = 10920
- Common difference, d = 16
The number of rows (i.e. the number of terms) is calculated using:

So,we have:

Evaluate the terms and factors

Evaluate the like terms
21840 = n(424+ 16n)
Expand
21840 = 424n + 16n^2
Rewrite as:
16n^2 + 424n - 21840 = 0
Using a graphical tool, we have:
n = 26
Hence, the number of rows in the arena is 26
Read more about arithmetic sequence at:
brainly.com/question/6561461
#SPJ1