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kondor19780726 [428]
3 years ago
6

Why was the United States Constitution created in 1787?

Mathematics
2 answers:
Lisa [10]3 years ago
5 0
C, The articles of confederation didn't work for everyone, so the Constitution was created
Vladimir79 [104]3 years ago
4 0

Answer:

the answer is c

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Help pls! 37 points.
Mademuasel [1]

Answer:

<u>7 squares</u>

Step-by-step explanation:

<u>Key skills: Counting, Averages</u>

1) Based on what I counted, there are 11 columns, and 53 squares. If you want an average of 5 squares per column and you have 12 columns, the total number of squares you want is 60.

2) Since there are already 53 squares present, you need 60-53 = <u>7 squares</u> more.

<em>Hope you understood and have a nice day!!</em>

5 0
3 years ago
Read 2 more answers
Help me with this pls
monitta
25 - 8 = 17
She had 17 games at first
hope this helps!
4 0
3 years ago
Read 2 more answers
Whats the answer to this?
stellarik [79]

Step-by-step explanation:

area of figure = 5x² + 3

plz mark my answer as brainlist plzzzz.hope this will be helpful to you if you find it useful ☺️

8 0
3 years ago
Tom and Susan park at different lots.
Alenkinab [10]

Answer:

Tom = 5

Susan = 3

Step-by-step explanation:

FROM THE BOXPLOT :

Tom's IQR :

IQR = Q3 - Q1

Q3 = third quartile (value at the endpoint of the box)

Q1 = 1st quartile (value at the beginning of the box)

IQR = 9 - 4

IQR = 5

SUSAN :

IQR = Q3 - Q1

Q3 = third quartile (value at the endpoint of the box)

Q1 = 1st quartile (value at the beginning of the box)

IQR = 8 - 5

IQR = 3

7 0
3 years ago
eight cards are drawn from a standard deck of 52 cards. how many hands off with cards contain exactly three queens and three jac
d1i1m1o1n [39]

Answer:

15,136 hands off with cards contain exactly three queens and three jacks.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Standard deck:

4 queens and 4 jacks.

The other 52 - 8 = 44 cards are neither queens nor jacks.

Wow many hands off with cards contain exactly three queens and three jacks?

3 queens from a set of 4.

3 jacks from a set of 4.

2 other cards(not queens neither jacks) from the other 44. So

C_{4,3}C_{4,3}C_{44,2} = \frac{4!}{1!3!} \times \frac{4!}{1!3!} \frac{44!}{2!42!} = 4*4*22*43 = 15136

15,136 hands off with cards contain exactly three queens and three jacks.

4 0
3 years ago
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