The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Answer:
Options 2), 4 , and 5 are CORRECT
Step-by-step explanation:
Notice that z * 3 1/3 = z * (3 + 1/3) = z * (9/3 + 1/3) = z * 10/3 = 10/3 z
1) The first option is not good'
2) 6 z - 2/3 z - 3 z + z = 4 z - 2/3 z = 12/3 z - 2/3 z = 10/3 z So this option is CORRECT
3) z * 4 - 2/3 is not good since 2/3 is not multiplied by z
4) z ( 4 - 2/3) = z (12/3 - 2/3) = z * 10/3 so this one is CORRECT
5) z (1 / 3 + 3) = z ( 1/3 + 9/3 ) = z (10/3) So this one is also CORRECT
Answer:
THE ANDER IS EHE DUDUDUSU
First, find the difference between the two prices. Then, divide the difference by the cost price.
75/50 = 1.5, or 150 percent
$143.47 Would be the answer your looking for.
